Ask question

Ask question

All categories

3 years ago

14

2m+n=7 4m+3n=-10 Solve using substitution method

1 answer:

jeka57 [31]3 years ago

5 0

Answer:

m=31/2, n=-24. (31/2, -24).

Step-by-step explanation:

2m+n=7

4m+3n=-10

-------------------

n=7-2m

4m+3(7-2m)=-10

4m+21-6m=-10

-2m=-10-21

-2m=-31

2m=31

m=31/2

2(31/2)+n=7

31+n=7

n=7-31

n=-24

You might be interested in

Need help ASAP! Please show work

anygoal [31]

The answer is f because if you find the average between 78 and 62 you get 70

5 0

3 years ago

If LM = 20 cm, and PQ = 16 cm, what is the length of RM, in centimeters?

LuckyWell [14K]

Answer:

RM = 12 cm

Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

Assuming 20 is the hypotenuse cus there is no picture:

$a^{2} + 16^{2} = 20^{2}$

$a^{2} +256 = 400$

$a^{2} = 144$

$a=144$

If It's not the hypotenuse:

$16^{2}+ 20^{2} =c^{2}$

$256+400 =c^{2}$

$656=c^{2}$

$c = 25.61249695$

But I find it unlikely that 20 wasn't the hypotenuse so ignore that unless it applies.

Hope this helped. :0)

5 0

3 years ago

Will give Brainliest! What is the simplified form of the seventh root of x to the fifth power times the seventh root of x to the

jekas [21]

Answer:

2) x times the seventh root of x cubed

Step-by-step explanation:

$\displaystyle\sqrt[7]{x^5}\cdot\sqrt[7]{x^5}=\sqrt[7]{x^{5+5}}\\\\=\sqrt[7]{x^{7+3}}=\sqrt[7]{x^7}\cdot\sqrt[7]{x^3}\\\\=x\sqrt[7]{x^3}$

4 0

3 years ago

Find the polynomial of least degree to be added to 6x^2+8x^3+17x^2+12x+7 so that 3x^2+4x+1 is a factor. Class ten questions

AURORKA [14]

Hope that really helps you

3 0

2 years ago

Answer as many as you can please (write in slope-intercept form)

RoseWind [281]

Answer: See below

Step-by-step explanation:

For the first one, we are already given our slope. All we need to do is find the y-intercept, b.

y=-2x+b

6=-2(-3)+b

6=6+b

b=0

The slope-intercept form is y=-2x.

For the second one, we need to first find the slope using $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ .

$m=\frac{1-13}{3-(-6)} =\frac{-12}{9}$

Now that we have our slope, we can plug it into our slope-intercept form to solve for b.

$y=-\frac{12}{9} x+b$

$3=-\frac{12}{9}(1)+b$

$-\frac{9}{4} =b$

The slope-intercept form is $y=-\frac{12}{9} -\frac{9}{4}$ .

For the third one, we are already given the slope, so all we have to do is find b.

$y=-\frac{1}{2}x +b$

$-7=-\frac{1}{2} (-4)+b$

$-7=2+b$

$-9=b$

The slope-intercept form is $y=-\frac{1}{2} x-9$ .

For the last one, we need to first find the slope using $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ .

$m=\frac{-8-2}{3-1}=\frac{-10}{2} =-5$

Now that we have our slope, we can plug it into our slope-intercept form and find b.

$y=-5x+b$

$2=-5(1)+b$

$2=-5+b$

$7=b$

Our slope-intercept form is $y=-5x+7$ .

4 0

3 years ago