Given that AXB is complementary to both CYD and FZE and m AXB=20 degrees what is m CYD+m FZE?
2 answers:
We know that AXB + CYD and AXB + FZE = 90
20 + CYD = 90 and 20 + FZE = 90
We can see that CYD and FZE are equal so we can use one equation
Let's use 20 + CYD = 90
CYD = 70 and FZE is also equal to 70 because CYD and FZE are equal.
so 70 + 70 = 140 degree
It is given that, AXB + CYD = 90
So, CYD = 90 - AXB
CYD = 90 - 20 = 70
Agaian, AXB + FZE = 90
FZE = 90 - AXB
FZE = 90 - 20 = 70
So, CYD + FZE = 70 + 70 = 140
In short, Your Answer would be: 140 degrees
Hope this helps!
You might be interested in
The answer is B through ASA (Angle-Side-Angle) similarity criterion.
Answer:
4√(xy³)
Step-by-step explanation:
8√(x²y⁶)
The above expression can be simplified as follow:
8√(x²y⁶)
Recall:
m√a = a^1/m
Therefore,
8√(x²y⁶) = (x²y⁶)^1/8
Recall:
(aⁿ)^1/m = a^(n/m)
Therefore,
(x²y⁶)^1/8 = x^(2/8)•y^(6/8)
= x^1/4•y^3/4
= (xy³)^1/4
Recall :
a^1/m = m√a
Therefore,
(xy³)^1/4 = 4√(xy³)
Therefore,
8√(x²y⁶) = 4√(xy³)
An ordered pair of the inverse of f(x)D, (1.2)
Answer:i'm pretty sure it is 2.3 lbs
Step-by-step explanation:what i did was ...
3.5 multiplied by 2.80 then divided by 4.20