All categories

2 years ago

Given that AXB is complementary to both CYD and FZE and m AXB=20 degrees what is m CYD+m FZE?

2 answers:

8 0

We know that AXB + CYD and AXB + FZE = 90

20 + CYD = 90 and 20 + FZE = 90

We can see that CYD and FZE are equal so we can use one equation

Let's use 20 + CYD = 90

CYD = 70 and FZE is also equal to 70 because CYD and FZE are equal.

so 70 + 70 = 140 degree

makkiz [27]2 years ago

4 0

It is given that, AXB + CYD = 90
So, CYD = 90 - AXB
CYD = 90 - 20 = 70

Agaian, AXB + FZE = 90
FZE = 90 - AXB
FZE = 90 - 20 = 70

So, CYD + FZE = 70 + 70 = 140

In short, Your Answer would be: 140 degrees

Hope this helps!

You might be interested in

A candy box measures 8.2 cm in diameter and 15 cm in height. How many 2 cm cubed pieces of candy can fit into the box?

Katarina [22]

60 2cm candy prices can fit because if you multiply 8.2 by 15 it equals a decimal and if you divide it by 2 that the nearest whole number you’ll get is 60, so the answer has to be 60.

8 0

2 years ago

Greg and Heather each opened a savings account today. Greg opened his account with a starting amount of $330, and he is going to

cluponka [151]

Set up two equations:

Greg = 330 + 75X

Heather = 660 + 45x

Set them to equal and solve for x:

330 + 75x = 660 + 45x

Subtract 330 from both sides:

75x = 330 + 45x

Subtract 45x from both sides:

30x = 330

Divide both sides by 30:

x = 330 / 30

X = 11

11 months they will have the same amount saved.

6 0

2 years ago

Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?

Nikolay [14]

The inclusion/exclusion principle states that

$|X\cup Y|=|X|+|Y|-|X\cap Y|$

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, $|X\cup Y|$ will have the most elements when the sets $X$ and $Y$ are disjoint, i.e. $X\cap Y=\emptyset$ , which would mean the most we can can in this case would be

$|X\cup Y|=|X|+|Y|=22+13=35$

(Note that $n(X)=|X|$ denotes the cardinality of the set $X$ .)

3 0

3 years ago

HELP WITH 4 QUESTIONS!!!!

m_a_m_a [10]

When dilation is about the origin, as it is here in every case, the image point coordinates are the original (pre-image) coordinates multiplied by the scale factor.

1. Multiply every coordinate value by 5:

... W' = (-5, 10), X' = (-15, -5), Y' = (25, -5), Z' = (15, 10)

2. Multiply every coordinate value by 1/3:

... A' = (-2, 5), B' = (0, 5/3), C' = (1, 10/3)

3. A' = (2, 8), B' = (6, 2), C' = (2, 2)

4. The image coordinates are 5 times the original coordinates, so ...

... the scale factor of the dilation is 5.

5 0

2 years ago

Please help me answer this question its urgent

yarga [219]

Answer: