Answer:
B=![\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's do the multiplication AB.
If A=![\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!
The answer is C (289pi/6 mi2)
Answer:
AC = 12.4 km (nearest tenth)
Step-by-step explanation:
AC can be calculated by using Pythagorean Theorem.
Thus:
AC² = AB² + BC²
Plug in the values
AC² = 8² + 9.5²
AC + √{154.25)
AC = 12.4 km (nearest tenth)
Answer:
The graph that have 2 lines is for Question 21 and the graph with three lines is for Question 22
Step-by-step explanation: