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2 years ago

Can anyone help me please? Also explain if you can. Thank you :)

Mathematics

1 answer:

djverab [1.8K]2 years ago

3 0

The answer is 6/9 or 2/3 because 2X2X2=8 and 9X9X9=729......it equals 8/729

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Louise begins factoring the polynomial, which has four terms.

ad-work [718]

Louise wants to factorize completely the given polynomial $4x^{3}+12x^{2}+5x+15$

Grouping first, second terms together and third, fourth terms together

= $4x^{3}+12x^{2}+5x+15$

Taking $4x^{2}$ common from first and second terms of the given expression and taking 5 common from the third and fourth terms.

= $=4x^{2}(x+3)+5(x+3)$

Taking (x+3) common from the given expression,

= $=(4x^{2}+5)(x+3)$ is the completely factored form.

5 0

3 years ago

Give three additional ways to name Plane M.

ololo11 [35]

65 and 2 are wsys too your welcome

6 0

3 years ago

Which function has the greatest rate of change?<br>plzzz help ASAP

Andreyy89

The answer is A because the rate of change is 7.
You can find this by writing it from standard form to slope intercept (y = mx+b).

B is 6, C is 5, and D is also 5 (all lower than 7)

3 0

3 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago

Fill in the blanks:

ser-zykov [4K]

Answer:

$8943=8\times 1000+9\times 100+4\times 10+3\times 1=8\times 10^3+9\times 10^2+4\times 10^1+3\times 1$

So in blanks there will be 8, 9, 4, 3

Step-by-step explanation:

We have given that $8943=.....\times 1000+....\times 100+....10+....1=....10^3+....10^2+....10^1+....1$

We have to fill the blanks

We know that $8\times 1000=8000$

$9\times 100$

$4\times 10$

$3\times 1$

When we add all then

$8000+900+40+3=8943$

So in the blanks there will be 8 , 9, 4 , 3

We also know that $8000=8\times 10^3$

$900=9\times 10^2$

$40=4\times 10^1$

$3\times 1=3$

So $8943=8\times 1000+9\times 100+4\times 10+3\times 1=8\times 10^3+9\times 10^2+4\times 10^1+3\times 1$

7 0

3 years ago