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alexgriva [62]
2 years ago
5

Solve the following inequalities (picture attached)

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
6 0
34.
(a) A. x < 4
(b) p > 1
(c) y <span>≤ 2.8

I love solving inequalities. I hope you find this answer the most helpful! :)</span>
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Mrs. Walker is instructing a team of students on designing the sailboat shown. Beth is working on the smaller sail, which is a r
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Answer: OPTION C.

Step-by-step explanation:

1. To solve this problem you must apply the Pythagorean Theorem, which is shown below:

a^{2}=b^{2}+c^{2}

Where a is the hypotenuse, and b and c are the legs of the triangle.

2. When you solve for one of the legs and substitute values, you obtain that the result is:

b=\sqrt{a^{2}-c^{2}}\\b=\sqrt{(24.8ft)^{2}-(8ft)^{2}}\\b=23.5ft

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The table below shows the relationship between m and p, where the independent variable is p.
scoray [572]

Answer:

C

Step-by-step explanation:

P is an independent variable, therefore making M a dependent variable.

B and D are not it.

When plugging in P in choice A, M has a different answer than in the list.

A is not it.

When pluggin in P in choice C, M has the same answers as in the list.

C is the answer

5 0
2 years ago
I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!
frutty [35]

Answer:

17) x=8

18) x=\sqrt{189} or x= 3\sqrt{21}

Step-by-step explanation:

So the rule is a^{2} +b^{2} =c^{2}, "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

                                               x^{2} +x^{2} =(8\sqrt{2})  ^{2}

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)    

                                                2x^2=8^2(\sqrt{2} )^{2}  

                                                  2x^2=64(2)

                                                   2x^2=128    

                                                  x^{2}= 128/2  

                                                     x^{2} =64

                                                        x=8      

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

                                                    c^{2} - b^{2} = a^{2}

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

                                                   15^{2} -6^{2} =x^{2}

                                                   225-36=x^{2}  

                                                     x^{2} =189

                                               x=\sqrt{189}=3\sqrt{21}

        The more you do these, the easier they'll get, so don't worry!

                           

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3 dollars a d 20 cents I hope
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