You have two fair, six-sides dice. However, the dice have been modified so that instead or 1,2,3,4,5,6 the sides are numbered 1,
1 answer:
Answer:
30.56%
Step-by-step explanation:
Let the sides on each dice be labeled as 1, 2a, 2b, 2c, 3, 4.
The sample space for the sum of the values being 4 is:
S={1,3; 3,1; 2a,2a; 2a,2b; 2a,2c; 2b,2a; 2b,2b; 2b,2c; 2c,2a; 2c,2b; 2c,2c}
There are 11 possible sums out of the 36 possible outcomes that result in a sum of 4. Therefore, the probability their total is 4 is:
There is a 30.56% probability that their sum is 4.
You might be interested in
<h2>Answer:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
<em />
First of all, let's name the first variable which is the smaller number. Accordingly, the lager number will be
given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:
So:
1. The sum of 2 consecutive integers can be written as:
2. Nine times the smaller and 5 times the larger can be written as:
Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:
The two numbers are: