The given plane,
, has normal vector
. Any plane parallel to this one has the same normal vector.
Let
be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

and this is perpendicular to
.
So the equation of the plane is

or equivalently,

Answer:
Step-by-step explanation:
There's no "solving" to be done because its an expression, but im assuming the question wants you to factor.

First, factor out a b^2

Factor the trinomial. What two numbers multiply to equal -10 but add to equal -3? They are -5 and +2

Answer:
Both graphs have a “y-intercept” at (0,0), so i believe the answer would be they don’t have y intercepts
Step-by-step explanation:
Answer:
Step-by-step explanation:
Integer roots:
a = 6 n + 1, b = 7, c = -3 n^2 - n, n element Z
a = 6 n + 5, b = 7, c = -3 n^2 - 5 n - 2, n element Z
Derivative:
d/da(1/7 (a^2 + 12 c) b - 1) = (2 a b)/7
Indefinite integral:
integral(-1 + 1/7 b (a^2 + 12 c)) da = (a^3 b)/21 + (12 a b c)/7 - a + constant
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