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lana66690 [7]
3 years ago
14

When constructing a circle inscribed in a triangle, what is the purpose of constructing a perpendicular segment from the incente

r to a side of the triangle?
To determine the center of the circle
To determine the radius of the circle
To connect the midpoints of each side of the triangle
To connect the arc markings from the angle bisectors

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0
Please refer to the picture I've attached.

When a circle is inscribed in a triangle, it means that the circle is drawn inside a triangle such that the midpoints of each side of the triangle are tangent to the circle. By doing this, you draw the biggest circle that could fit inside a triangle.

Now, the circle and the triangle have the same center illustrated here by the red dot. When you connect all sides of the triangle to the center (yellow lines), you create three equal angles. This is equal to 360 (one revolution) divided by 3, equals 120°. But when you create a perpendicular bisector from the center (black line), the angle is halved. It will now be 120/2 = 60°. Usually you are given the sides of the triangle. By using pythagorean theorems, you can find, therefore, the radius of the circle. To illustrate, the radius is equal to (s/2)/tan60.

Thus, the answer is: <span>To determine the radius of the circle.</span>

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Answer:

The lower quartile is Q_1=33 thousand dollars.

The median quartile is Q_2=39 thousand dollars.

The upper quartile is Q_3=45 thousand dollars.

Step-by-step explanation:

The lower quartile is the median value of the lower half of a data set at the 25th percentile of a distribution.

The median quartile is the median value of a data set at the 50th percentile of a distribution.

The upper quartile is the median value of the upper half of a data set at the 75th percentile of a distribution.

To locate each quartile in a data set, we follow four steps:

Step 1: Put the numbers in order: 23, 25, 33, 34, 39, 39, 44, 45, 48, 55

Step 2: The median is given by \frac{n+1}{2} where n is all scores in the data set.  

Because n = 10, the median position is \frac{10+1}{2}=5.5

The median is the average of the fifth and sixth positioned scores

Q_2=\frac{39+39}{2} =39

Step 3:  Compute \frac{n+1}{2} where n is all scores below Q_2.

For scores below Q_2, use only 23, 25, 33, 34, 39.

Because n = 5, the median position is \frac{5+1}{2}=3

The median is the third positioned score: Q_1=33

Step 4: Compute \frac{n+1}{2} where n is all scores above Q_2.

For scores above Q_2, use only  39, 44, 45, 48, 55

Because n = 5, the median position is \frac{5+1}{2}=3

The median is the third positioned score: Q_3=45

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3 years ago
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Step-by-step explanation:

7 + y < 12 it can also be written as

7 + y = 12

y = 12 - 7

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y < 5

Hope it will help :)

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Step-by-step explanation:

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