Can someone pls help me by tonightttt

A diagonal of a cube measures 15 cm and the length of an edge of the cube is startroot 75 endroot cm. what is the length of the

Veseljchak [2.6K]

A cube is a three-dimensional solid object having six square faces. The measure of the length of the diagonal of the face of the cube is 12.2 cm.

A cube is a three-dimensional solid object having six square faces, facets, or sides, three of which meet at each vertex. The cube is one of the five Platonic solids and the only regular hexahedron.

Given the length of an edge of the cube is √75 cm, therefore, the length of the diagonal of the face of the cube will be √2 times the length of an edge of the cube. Thus, the measure of the length of the diagonal of the face of the cube is,

Length of the diagonal of the face = √2 × √75 = 12.2 cm

Hence, the measure of the length of the diagonal of the face of the cube is 12.2 cm.

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3 0

2 years ago

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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

(H/6 )- (1) Solve for H Please help me

likoan [24]

All you need to do for this is remove the parenthese and your answer will be $\frac{H}{6} -1$ because that's the furthest it can be simplified.

4 0

4 years ago

Please help! Will give Brainliest!

kkurt [141]

Answer:

g(x) = 2|x|
g(x) = -2|x|
g(x) = -2|x| -3
g(x) = -2|x-1| -3

Step-by-step explanation:

1) Vertical stretch is accomplished by multiplying the function value by the stretch factor. When |x| is stretched by a factor of 2, the stretched function is ...

g(x) = 2|x|

__

2) Reflection over the x-axis means each y-value is replaced by its opposite. This is accomplished by multiplying the function value by -1.

g(x) = -2|x|

__

3) As you know from when you plot a point on a graph, shifting it down 3 units subtracts 3 from the y-value.

g(x) = -2|x| -3

__

4) A right-shift by k units means the argument of the function is replaced by x-k. We want a right shift of 1 unit, so ...

g(x) = -2|x -1| -3

7 0

3 years ago

Simplify 136 + 81. 36 + 81 =

Bond [772]

Answer:

298.36

Step-by-step explanation:

5 0

3 years ago

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