A=(-6,-2)
B=(6,2)
![\sqrt{[(6-(-6)]^2+[(2-(-2)]^2} = \sqrt{12^2+4^2} = \sqrt{16} =4 \sqrt{10}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%286-%28-6%29%5D%5E2%2B%5B%282-%28-2%29%5D%5E2%7D%20%3D%20%5Csqrt%7B12%5E2%2B4%5E2%7D%20%3D%20%5Csqrt%7B16%7D%20%3D4%20%5Csqrt%7B10%7D%20)
B=(6,2)
Name three decimals between 0.8 and 0.9
2 answers:
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Answer:
50 units
Step-by-step explanation:
you use Pythagorean-theorem which means A^2+B^2 =C^2
It does not matter the order of A and B because it is adding. But C is the hypotenuse.
If we plug in the # this is what it looks like...
14^2 +48^2=C^2
or
48^2+14^2=C^2
14*14= 196
48*48=2,304
then you add
196+2,304=C^2
2,500= C^2
and you can use a calculator for this part you do 2,500
with the 2,500 you use the sign as in the picture and it gives you...
50
which means 50*50 = 2,500
