Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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Yeah because he was at least 80% and when you add the grain and carbon that was total. Then divide the carbon. It will be 80%
Finding slope?
5. Slope is 5/3
6. Slope is 7/3
7. Slope is -3
8. Slope is 7/3
Just do rise/run
X = −19.30434782608696
You need me to explain?
