Answer:
< 2.11, 4.53 >, < -3.03, -1.75 >, <2.93 cos 108.26, 2.93 sin 108.26 >
Step-by-step explanation:
First, let's decompose Bruce's velocity along the x- and y- direction. Bruce is moving 5 m/s at 25 degrees east of north, so its angle with respect to the positive x-direction is actually 90 - 25 = 65 degrees. So its components are
So, Bruce's vector is
< 2.11, 4.53 >
The current is moving 3.5 m/s at an angle 60 degrees west of south, which means an overall angle of 210 degrees, measured counterclockwise from the positive x-axis. So, the components of the current's velocity are
So, the current's vector is
< -3.03, -1.75 >
Finally, we can add the components of the two vectors to find Bruce's actual velocity:
So, Bruce's actual velocity is
< -0.92, 2.78 >
The magnitude is
And the direction is