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3 years ago

PLEASE HELP ASAP 25 points.

Mathematics

2 answers:

prohojiy [21]3 years ago

3 0

Answer:

d, no solutions

Step-by-step explanation:

Natasha2012 [34]3 years ago

3 0

The answer to this question is D because it is impossible for the equation to be true

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PLEASE HELP! :D Triangle ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC.

OverLord2011 [107]

I'm pretty sure you can just use a Cartesian plane and since all of your points are (positive, positive) they'd all be in the First Quadrant (top right)

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4 years ago

There are 252 campers at a summer sports camp. How

Taya2010 [7]

18 teams
Just divide 252 by 14:)

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3 years ago

Read 2 more answers

To make lemonade, you used one quart of water, one pint of lemon juice, and 9 ounces of your secret ingredient: honey. How much

WITCHER [35]

To solve this problem you must follow the proccedure shown below:

1. Amount of lemonade in pints:

1 quart of water=2 pints
1 pint of lemon
(9 ounces of honey)(0.0625 pints/1 ounce)=0.56 pints

Total in pints=2 pints+1 pint+0.56 pints
Total in pints=3.56 pints

2. Amount of lemonade in cups:

Total in cups=(3.56 pints)(2 cups/1 pint)
Total in cups=7.12 cups

3. Amount of lemonade in ounces:

Total in ounces=(7.12 cups)(8 ounces/1 cup)
Total in ounces=56.96 ounces

4 0

3 years ago

a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

It is assumed that weight of pyramid is proportional to its volume.

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

Since, base and height of small pyramid and original pyramid are in proportion.

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

Learn more:

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6 0

3 years ago

Read 2 more answers

A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec

Bas_tet [7]

Speed of the ship in the second hour = (62.5 * x ) / 100 kph.

In third hour it is [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again so we can now form the equation

62.5x x x
------- * ---- * ---- = 32
100 100 100

62,5 x^3 = 32,000,000
x^3 = 512,000
x = 80 <----- Answer to (a)

(b) Ship travels 62.5 in first hour then this falls by a common ratio of 0.8 each hour so we have a geometric sequence

Dist travelled in 6 hours = a1 1 - r^n
-------- = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56

1 - r

Answer is 230.56 km

5 0

3 years ago