To cover at least 170.5 sq.ft. the width must be at least 11 feet
W=170.5sq.ft / 15.5 ft = 11ft
It would be 32-4x=12
32-4(5)=12
32-20=12
12=12
Answer:
C. (0.9, 0.3)
Explanation:
![\rightarrow \sf \dfrac{1}{4^{x}} = \log(2x)](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20%20%5Cdfrac%7B1%7D%7B4%5E%7Bx%7D%7D%20%3D%20%5Clog%282x%29)
The above given equation is critical to solve algebraically thus they have mentioned to solve it using a technology - graphing calculator.
<h3><u /></h3><h3><u>When graphed the following equations</u>:</h3>
They meet each other at: (0.9371, 0.2728)
(0.9, 0.3)
You would need 3 pails of plaster, specifically about 2 pails and a fifth of another but you cant buy a fraction of a pail, so 3 pails are needed.