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marin [14]
3 years ago
7

What can you conclude about perpendicular lines that are drawn in the coordinate plane? (Assume the lines are not aligned horizo

ntally and vertically).
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0
The lines will cross each other
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It is hard to see the picture.

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In ΔABC, a = 300 inches, ∠B=45° and ∠C=41°. Find the length of c, to the nearest 10th of an inch.
dezoksy [38]

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197.3

Step-by-step explanation:

4 0
3 years ago
The net of a pyramid is shown below:
Shalnov [3]

Answer:

Step-by-step explanation:

height of pyramid = √(10²-(5/2)²) = √93.75

volume of pyramid = ⅓b²h = ⅓·5²√93.75 ≅ 80.69 in³

lateral area = 2×5×10 = 100 in²

base area = 5² = 25 in²

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6 0
2 years ago
I need help on this question
pogonyaev

Answer:

315

Step-by-step explanation:

1. This is not a scale rectangle and it angers me.

2. All you have to do is draw proportions.

5x7=35

15x21=315

Youll notice that 5x3=15 and 7x3=21 so it’s just proportions!

5 0
3 years ago
ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
Alex Ar [27]

NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
  • square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
  • cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

3 0
2 years ago
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