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Sati [7]
3 years ago
5

Which element’s atoms have the greatest average number of neutrons?Which element’s atoms have the greatest average number of neu

trons?
Physics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

Tennessine

Explanation:

The nucleus of an atom contains protons and neutrons. These are subatomic particles. Proton is positively charged while a neutron is a neutral particle. Both these particles have similar mass.

The element whose atom has greatest average number of neutrons is Tennessine. It has 177 neutrons.

Nutka1998 [239]3 years ago
7 0
When an atom has a high neutron-to-proton ration, that atom is very unstable and thus, radioactive. The more neutrons an atom has, the more radioactive it is. So,it is only logical that the element with the greatest number of neutrons is Uranium. It has 140 neutrons.
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S_A_V [24]

Answer:

-148,6 MJ

Explanation:

Dado que la liberación de calor al medio ambiente es;

H = mcθ

Dónde;

m = masa de agua

c = capacidad calorífica específica del agua

θ = aumento de temperatura

H = 1220 kg × 4200 × [-29-0]

H = -148,6 MJ

5 0
3 years ago
The earth gravity field strength in the south pole is less than the north pole. Explain
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Answer:

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3 0
3 years ago
If a person is throwing darts at a target, and shoots three in a row in the same spot on the 20 section outer ring, but none in
Gwar [14]
a) precise but not accurate. 

this is because the thrower was capable to repeat the same result everytime but it was not the desire outcome.
6 0
3 years ago
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How does Newton's third law explain how a rocket is launched upward?
MrRissso [65]
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3 years ago
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Block 2 of mass 1.00 kg is at rest on a frictionless surface and touching the end of an unstretched spring of spring constant 20
son4ous [18]

Answer:

x = 0.327 m

Explanation:

Block 2 of mass 1.00 kg is at rest

spring constant = 200 N/m            

Block 1 of mass 2 kg moving at 4 m/s

m₁ v₁ = (m₁ + m₂)V                                

2 x 4 = (2 + 1) V                                                      

V = 2.67 m/s                                                        

loss of kinetic energy = gain elastic potential energy

\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2                  

\dfrac{1}{2}\times (3)\times 2.67^2 = \dfrac{1}{2}\times 200 \times x^2

x = 0.327 m

hence, the spring compressed distance is equal to x = 0.327 m

8 0
3 years ago
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