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kondor19780726 [428]
3 years ago
5

Con los datos recolectados en la clase anterior sobre la altura (13cm) y tiempo (1 s) de salto calcular la velocidad y la distan

cia recorrida de cada integrante del grupo.
Physics
1 answer:
goldfiish [28.3K]3 years ago
7 0

Answer:what

Explanation:

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The driver of a car wishes to pass a truck that is traveling at a constant speed of 20.0 m/s (about 45 mi/h). Initially, the car
Alex73 [517]

Answer:

15.8640053791 s

392.780107582 m

29.5184032275 m/s

Explanation:

0 denotes initial

x denotes displacement

c denotes car

t denotes truck

r denotes rear

x_0_{cr}=-49.5\ m

a_c=0.6\ m/s^2

x_0_{t}=0

v_0_{c}=v_0_{t}

For the car

x_c=x_0+v_0_{c}t+\dfrac{1}{2}at^2

The displacement of the truck will be

x_t=v_tt

From the above two equations we get

x_c-x_t=x_0+v_0_{c}+\dfrac{1}{2}at-v_{t}t=26\\\Rightarrow 26=x_0+\dfrac{1}{2}at^2\\\Rightarrow 26+49.5=\dfrac{1}{2}0.6t^2\\\Rightarrow t=\sqrt{\dfrac{2(26+49.5)}{0.6}}\\\Rightarrow t=15.8640053791\ s

The time taken is 15.8640053791 s

x-x_0=v_{0}_{c}t+\dfrac{1}{2}at^2\\\Rightarrow x-x_0=20\times 15.8640053791+\dfrac{1}{2}0.6\times 15.8640053791^2\\\Rightarrow x-x_0=392.780107582\ m

The distance the car travels is 392.780107582 m

v=v_0+at\\\Rightarrow v=20+0.6\times 15.8640053791\\\Rightarrow v=29.5184032275\ m/s

The velocity of the car is 29.5184032275 m/s

6 0
3 years ago
What does the area under a curve of a graph of velocity versus time yield? A. Average acceleration O B. Average velocity OC.Tota
frutty [35]

Answer:

option (D)

Explanation:

If we plot a graph between the velocity of the object and the time taken, the slope of graph gives the value of acceleration of the object and the area under the graph gives the product of velocity and time taken that means it is displacement

5 0
3 years ago
Read 2 more answers
A solid iron ball of mass 770 kg is used on a building site. The ball is suspended by a rope from a crane. The distance from the
Scrat [10]
From a balistics pendulum as an example, which is probably where you are at... Triangles, L = 12m, x_0 = 1.6, we need to find the angle (theta) sin (theta) = 1.6/12 = 0.1333.... theta = ArcSin(0.1333...) = 0.1337 rad Then, this is the height that the mass vertically raises in it's arc y_2 = L-L*cos(theta) = 0.107 m use y_2 in a kinematic swing... <span><span>v=sqrt(<span><span>2g<span>y_2)</span></span></span>=1.45m/s</span></span>
6 0
4 years ago
States that Earth processes today are similar to those that took place in the past
Maslowich

Answer;

Uniformitarianism

Explanation;

-Uniformitarianism is the principle suggesting that Earth's geologic processes acted in the same manner and with essentially the same intensity in the past as they do in the present and that such uniformity is sufficient to account for all geologic change.  For example, at an active volcano we can observe lava cooling to form layers of basalt.

James Hutton suggested that deep soil profiles were formed by the weathering of bedrock over thousands of years. He also suggested that supernatural theories were not needed to explain the geologic history of the Earth.

3 0
4 years ago
Read 2 more answers
This homework is meant to be in for today first lesson, please help!!!
Black_prince [1.1K]

The agriculture land needed to grow the willow is 1500000 Hectares

<h3>What is Power?</h3>

Power can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).

A coal burning power station burns 6 million tonnes of coal per kg. Coal has a average energy value of 29.25 MJ per year. Wood chip from willow trees has an energy value of 13 MJ per kg. A hectare of agricultural land can produce 9 tonnes of drt willow wood per year.

The coal consumption per year = 29.25 x 1000 x 6000000

                                                    =175500000000 MJ

If this power station burned dry willow wood instead of coal, agriculture land would be needed to grow the willow,

1 hectare of willow will produce 9 x 13x 1000 = 117000 MJ.

The agriculture land needed to grow the willow is

= 175500000000 MJ /  117000 MJ.

= 1500000 Hectares.

Thus, agriculture land needed is  1500000 Hectares.

Learn more about power.

brainly.com/question/15120631

#SPJ1

4 0
2 years ago
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