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sashaice [31]
3 years ago
12

How is the volume of the prism calculated

Mathematics
2 answers:
MakcuM [25]3 years ago
6 0

Answer:

Step-by-step explanation:

Volume=base×height

V=bh

lukranit [14]3 years ago
3 0

V=B·H

V is volume

B is Base

H is height

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aliya0001 [1]
C because it's using the distributive property. It's breaking it down into sections.
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3 years ago
The inside diameter of a randomly selected piston ring is a random variable with mean value 8 cm and standard deviation 0.03 cm.
S_A_V [24]

Answer:

a) P(7.99 ≤ X ≤ 8.01) = 0.8164

b) P(X ≥ 8.01) = 0.0475.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean

In this problem, we have that:

\mu = 8, \sigma = 0.03

(a) Calculate P(7.99 ≤ X ≤ 8.01) when n = 16.

n = 16, so s = \frac{0.03}{4} = 0.0075

This probability is the pvalue of Z when X = 8.01 subtracted by the pvalue of Z when X = 7.99. So

X = 8.01

Z = \frac{X - \mu}{\sigma}

Applying the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.0075}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 7.99

Z = \frac{X - \mu}{s}

Z = \frac{7.99 - 8}{0.0075}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918

0.9082 - 0.0918 = 0.8164

P(7.99 ≤ X ≤ 8.01) = 0.8164

(b) How likely is it that the sample mean diameter exceeds 8.01 when n = 25? P(X ≥ 8.01) =

n = 25, so s = \frac{0.03}{5} = 0.006

This is 1 subtracted by the pvalue of Z when X = 8.01. So

Z = \frac{X - \mu}{s}

Z = \frac{8.01 - 8}{0.006}

Z = 1.67

Z = 1.67 has a pvalue of 0.9525

1 - 0.9525 = 0.0475

P(X ≥ 8.01) = 0.0475.

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Which value of I makes the equation 6 (0.52 – 1.5) + 20 =-9- (1 + 6) true? 0 - 14 O1 14​
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(Giving Brainlyst)<br> Awnser this with the letter and fraction listed<br> EX. H- 2/3<br> Thanks!
Flura [38]

Answer:

C-7/8

R-8/9

P-61/66

L-11/18

I-3/4

A-7/12

O-47/55

H-29/40

S-28/33

T-4/5

M-11/12

E-71/84

U-13/42

N-19/20

I swear to god if I don’t get brainliest I’m going to lose it I haven’t done this math in like four years and it kinda took a while.... but I hope it helped u ☺️☺️☺️❤️❤️❤️❤️

Step-by-step explanation:

6 0
3 years ago
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