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3 years ago

PLEASE HELP GEOMETRY QUESTION

Mathematics

2 answers:

alisha [4.7K]3 years ago

4 0

The answer is 24.4 degrees

Eva8 [605]3 years ago

4 0

Answer:

24.4 degrees, you had it right!

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Pls help Suppose 30=a×60. What is 30a ?

Maslowich

Answer:

2 easy

Step-by-step explanation:

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2 years ago

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I need help on this please help me

sammy [17]

Answer: Please view the attachment.

Step-by-step explanation: Bur27con, I copied the photo you uploaded and edited it on Microsoft Word. The correct answer is shown in the document.

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2 years ago

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use the leading coefficient and degree of the polynomial function f(x)=x^3-7x^2+10x to determine the end behaviour of its graph.

Masja [62]

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The domain is all real numbers and the range is all real numbers as-well.

As x approaches infinity, so does y.

As x approaches -infinity, so does y.

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2 years ago

Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x

Greeley [361]

Answer:

Option (1)

Step-by-step explanation:

Given equation is,

$2^x=1-3^x$

To determine the solution of the equation we will substitute the values of 'x' given in the options,

Option (1)

For x = -0.75

$2^{-0.75}=1-3^{-0.75}$

0.59 = 1 - 0.44

0.59 = 0.56

Since, values on both the sides are approximately same.

Therefore, x = -0.75 will be the answer.

Option (2)

For x = -1.25

$2^{-1.25}=1-3^{-1.25}$

0.42 = 1 - 0.25

0.42 = 0.75

Which is not true.

Therefore, x = -1.25 is not the answer.

Option (3)

For x = 0.75

$2^{0.75}=1-3^{0.75}$

1.68 = 1 - 2.28

1.68 = -1.28

Which is not true.

Therefore, x = 0.75 is not the answer.

Option (4)

For x = 1.25

$2^{1.25}=1-3^{1.25}$

2.38 = 1 - 3.95

2.38 = -2.95

It's not true.

Therefore, x = 1.25 is not the answer.

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3 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

2 years ago

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