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barxatty [35]
4 years ago
5

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, pr

ovided that
Chemistry
1 answer:
Stella [2.4K]4 years ago
4 0
When presented with balanced chemical equation, the same phase can be cancelled out only when they appear to be in the opposite side of the equation. This means that in one equation, a certain chemical is a product. However, on the next equation, that same substance can be the reactant. 
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This force is opposing in nature .it resists object velocity .

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if the pressure on a 3.0 liter sample of gas is doubled at constant temperature, the new volume will be
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The new volume is 6.0 leters

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3 years ago
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Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

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3 years ago
The compound H2O is an example of a(n)
SashulF [63]
The answer you are looking for is water.
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4 years ago
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Dinitrogen pentoxide can be made by the reaction of nitrogen with oxygen. Consider the reaction
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The only reactants are Nitrogen and Oxygen and the only product is dinitrogen pentoxide. Following the law of conservation of mass, the total amount of reactants must equal the total amount of products. Thus, the total mass of dinitrogen pentoxide:
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