Answer:
13 and 14.
Step-by-step explanation:
So we have two consecutive integers.
Let's call the first integer a.
Since the integers are consecutive, the other integer must be (a+1) (one more than the last one).
We know that the sum of the greatest integer (or a+1) and twice the lesser integer (a) is 40. Therefore, we can write the following equation:

The first term represents the greatest integer. The second term represents 2 times the lesser integer. And together, they equal 40.
Solve for a. Combine like terms:

Subtract 1 from both sides. The 1s on the left cancel:

Divide both sides by 3:

Therefore, a or the first integer is 13.
And the second integer is 14.
And we can check:
14+2(13)=14+26=40
Answer:
hi hi hi hi hi
Step-by-step explanation:
plz follow me
Answer:
235
Step-by-step explanation:
42+1
43
3 times 43
129
129 times 2
258
258-23
235
Answer:
x = 3
Step-by-step explanation:
1.8 - 3.7x = -4.2x + 0.3
add -4.2x to both sides
1.8 - 0.5x = 0.3
subtract 1.8 from both sides
-0.5x = 0.3 - 1.8
-0.5x = -1.5
divide by -0.5 on both sides
x = 3
GREAT JOB!!!! YOU GOT IT!!! =)
Answer:20+10
Step-by-step explanation:It is 20 plus 10 because 6 times 5 is 30 and so is 20 plus 10.