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3 years ago

Please help !!!!!!!!

Mathematics

1 answer:

ivolga24 [154]3 years ago

4 0

Answer:

Step-by-step explanation:

162, 188, 197, 201, 266

a. add all number: 1014/ 5 = 202.8

b. 266-162 = 104

c. for each number subtract the mean and square the result.

1664.64+219.04+33.64+3.24+3994.24

= 5914.8/5 = 591.48

d. square root of variance

= 24.32

e. i don't know this one because i need the number of people in the family

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4 years ago

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3 years ago

33. Suppose you were on a planet where the

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Answer:

a) 3.675 m

b) 3.67m

Explanation:

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And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

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$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

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g2 = 9.8 $ms^-2$

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B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

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We get h1 = 3.67m which is the required height

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4 years ago