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Flura [38]
3 years ago
10

What is the base matterial for plastic wrap

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0
Plastic wrap basic material is <span>polyvinyl chloride or PVC.

Hope this helps, 

kwrob</span>
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Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1200 kg and was approaching at
igomit [66]

To resolve point A and B we need the concepts related to conservation of momentum (By collision) and Kinetic Energy. Conservation of momentum is given by the equation,

m_1\vec{v_1}+m_2\vec{v_2} = (m_1+m_2)\vec{v}

Our values in the statment are:

m_1 = 1200kg

v_1 = 6m/s

m_2 = 900kg

v_2 = 24m/s

Part A) As it is in an icy intersection, there is two different components (x,y) then,

1200(-6\hat{j})+900(-24\hat{i}) = (1200+900)\vec{v}

2100\vec{v} = -21600\hat{i}-7200\hat{j}

\vec{v} = -72/7\hat{i}-24/7\hat{j}

Then the magnitude is,

|\vec{v}| = 9.6525m/s

Part B) To obtain the Kinetic Energy Loss we need to use its equation, which is given by,

KE_i = \frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2

KE_i = \frac{1}{2}(1200)(6)^2+\frac{1}{2}(900)(24)^2

KE_i = 280.8kJ

The final energy is given by,

KE_f = \frac{1}{2}(m_1+m_2)v_f^2

KE_f = \frac{1}{2} (1200+900)(9.65)

KE_f =97778.625J

Then the change in Kinetic Energy is

\Delta KE = KE_f-KE_i = 97.778kJ- 280.8kJ

\Delta KE = -183.02kJ

<em>There was a loss of KE of 183.02kJ</em>

5 0
3 years ago
Una cuerda es puesta a vibrar 400 veces en 4 segundos Cual es la frecuencia del sonido emitido?
Readme [11.4K]

n = number of vibrations set in the string = 400 vibrations

t = total time taken for "n" vibrations set in the string = 4 second

f = frequency of the sound emitted due to vibrations set in the string


frequency of the sound emitted due to vibrations set in the string is given as

f = n/t

inserting the above values in the above formula

f = 400/4

f = 100 Hz

hence the frequency of sound comes out to be 100 Hz

4 0
3 years ago
Electric charges do not flow all the way through____________
valentinak56 [21]

Answer:

d

Explanation:

7 0
3 years ago
Read 2 more answers
A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?
PilotLPTM [1.2K]

Answer: E.

Explanation: because the book is on the table, its not really moving in any direction.

7 0
4 years ago
If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the 1200.-kg pick-up truck behind him continues tr
Alborosie

Answer: 20.2 m/s

Explanation:

From the question above, we have the following data;

M1 = 800kg

M2 = 1200kg

V1 = 13m/s

V2 = 25m/s

U (common velocity) =?

M1V1 + M2V2 = (M1 + M2). U

(800*13) + (1200*25) = (800+1200) * U

10400 + 30000 = 2000u

40400 = 2000u

U = 40400 / 2000

U = 20.2 m/s

5 0
3 years ago
Read 2 more answers
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