Answer:
24 hours

Explanation:
If a satellite is in sync with Earth then the period of each satellite is 24 hours.

Angular velocity is given by

The angular velocity of the satellite is 
C is the answer
The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?
a.
It faces the moon more often than other places on Earth.
b.
It has many rocky beaches.
c.
It is a long, narrow inlet.
d.
Its tides cannot be predicted accurately.
Answer:
Answer for the question is given in the attachment.
Explanation:
Answer:

Explanation:
c = Speed of wave
= Density of medium
A = Area
= Frequency

Intensity of sound is given by

So,

We get

The ratio is 