If there are 272.5 rotations in a mile, and 5280 ft in a mile, then there are 5280 ft in 272.5 rotations. Divide 5280 by 272.5 gives us 19.4 ft/rotation.
That's the circumference of the wheel, and since c = πd, 19.4/π = d, d = 6.2 ft. The diameter of the wheel is how tall it is.
Does this help? Any questions?
3 because 3•3 is 9 and 9•3 is 27
Consider the universal set U and the sets X, Y, Z. U={1,2,3,4,5,6} X={1,4,5} Y={1,2} Z={2,3,5} What is (Z⋃X′)⋂Y?
beks73 [17]
X' = U - X
= {1,2,3,4,5,6} - {1,4,5}
= {2,3,6}
(ZUX') = {2,3,5} U {2,3,6}
= {2,3,5,6}
(Z⋃X′)⋂Y = {2,3,5,6} ⋂ {1,2}
= {2}
Answer:
See attachment
Step-by-step explanation:
