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Mandarinka [93]
3 years ago
13

If Haylee entered the hospital at 4:00 pm july 7 and left the hospital at 11:00 am on july 11. how many hours was she in the hos

pital. Also explain please
Mathematics
2 answers:
lyudmila [28]3 years ago
7 0
She stayed in the hospital for 91 hours, because at 4:00pm there are 8 hours left in the day, so 8 hours go by and its july 8th, there are 3 days left until july 11th, there are 24 hours in a day,(3x24=72), then 11 hours go by until it's 11:00,(72+11=83). Then you add the 8 hours from before(83+8=91) Thats how you get the answer
vitfil [10]3 years ago
5 0
She was in the hospital for 91 hours because july 7th 4pm-july 10th 4pm is three days(72 hrs) and then july 10th 4pm-july 11th 11am is 12 hours. 72+12=91
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Write a point slope equation for -5/7 using the coordinates (6,2)
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Answer:

(13, -3)

Step-by-step explanation:

slope = -5/7

(6,2)  

m = ( y2 - y1) / ( x2 - x1 )

-5/7 = ( y2 - 2) / ( x2 - 6 )

   

    -5 = y2 -2

        +2        +2

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    +6         +6

      13 = x2


Check answer again by log them in:

m = ( y2 - y1 ) / ( x2 - x1 )

m = ( -3 - 2 ) / ( 13 - 6 )

m = -5 / 7


I hope this helps!

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rB-------> radius of the circle B
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the answer is
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