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Mandarinka [93]

3 years ago

13

If Haylee entered the hospital at 4:00 pm july 7 and left the hospital at 11:00 am on july 11. how many hours was she in the hos

pital. Also explain please

2 answers:

lyudmila [28]3 years ago

7 0

She stayed in the hospital for 91 hours, because at 4:00pm there are 8 hours left in the day, so 8 hours go by and its july 8th, there are 3 days left until july 11th, there are 24 hours in a day,(3x24=72), then 11 hours go by until it's 11:00,(72+11=83). Then you add the 8 hours from before(83+8=91) Thats how you get the answer

vitfil [10]3 years ago

5 0

She was in the hospital for 91 hours because july 7th 4pm-july 10th 4pm is three days(72 hrs) and then july 10th 4pm-july 11th 11am is 12 hours. 72+12=91

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On a coordinate plane, triangles R S T and L M N are shown. Triangle R S T has points (5, 5), (2, 1), and (1, 3). Triangle L M N

ivolga24 [154]

Answer:

LMN has a larger area

Step-by-step explanation:

Given

RST

$R =(5,5)$

$S= (2,1)$

$T = (1,3)$

LMN

$L = (0,-1)$

$M= (2,-4)$

$N= (-2,-3)$

Required

Compare both areas

The area of triangle is:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|$

For RST, we have:

$Area = \frac{1}{2}|5*1 - 2*5 + 2*3 - 1*1 + 1*5 - 5*3|$

$Area = \frac{1}{2}|-10|$

Remove absolute signs

$Area = \frac{1}{2}*10$

$Area = 10$

For LMN, we have:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|$

$Area = \frac{1}{2}|0*-4-2*-1+2*-3--2*-4--2*-1-0*-3|$

$Area = \frac{1}{2}|-14|$

Remove absolute signs

$Area = \frac{1}{2}*14$

$Area = 7$

<em>By comparing both areas, we can conclude that LMN has a larger area</em>

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3 years ago

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

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Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

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3 years ago

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Ronch [10]

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The answer to your question is: 2, 4, 5, 1 , 3

Step-by-step explanation:

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The next line is the fifth

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The next line is the first

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The last line is the third

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3 years ago

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