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3 years ago

2×+y=0, ×-y=6 what is the solution to this system of equations?

1 answer:

6 0

2×+y=0,
×-y=6

Add the 1st to the 2nd equation==> 3x +y-y=6+0==> 3x=6 & x=2

Plug 2 into any of the equation & you will get y=-4

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A carpenter contracts to do a job.The costs for the job are$2,000 for materials,$500 for labor, and $150 for equipment rental.Wh

Mekhanik [1.2K]

I think that the answer is 2,800

3 0

2 years ago

Luis tenía un saco de patatas de 95 kg. Ha vendido 10bolsas de 2,5kg cada una. ¿Cuántos kilos de patatas le quedan?

stepan [7]

Answer:

A Luis le quedan 70 kg de patatas.

Step-by-step explanation:

Para encontrar la respuesta, primero tienes que determinar la cantidad total de patatas que Luis ha vendido multiplicando la cantidad de kilos en cada bolsa por el número de bolsas vendidas:

2,5kg*10=25 kg

Ahora que sabes que Luis ha vendido 25 kg de patatas puedes restar esto de la cantidad de kilos que tenía para saber cuánto le queda:

95-25=70

De acuerdo a esto, la respuesta es que a Luis le quedan 70 kg de patatas.

8 0

2 years ago

If x=2 ,y=12 and x=4,y=3,find n and k if y is inversely proportional to x and k is a constant

Setler [38]

question:

x=2 ,<em>y</em>=12 and x=4,y=3,find n and k if y is inversely proportional to x and k is a constant

answer:

k=12 x=3 n=4

explain:

that the answer because the question said find the k and x and n so I find them

8 0

2 years ago

An exponential function is expressed in the form y=axb^x. The relation represents a growth when _______ and a decay when ______.

seropon [69]

Answer:

Growth when: b>1.

Decay when: 0<b<1.

Step-by-step explanation:

Any function in the form $f(x)=a{\times}b^x$ , where a > 0, b > 0 and b not equal to $1$ is called an exponential function with base b.

If 0 < b < 1 this is an example of an exponential decay.

The general shape of an exponential with b > 1 is an example of exponential growth.

Hence,

An exponential function is expressed in the form $f(x)=a{\times}b^x$ , The relation represents a growth when b >1 and a decay when 0<b<1.

5 0

2 years ago

The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc

Ludmilka [50]

Answer:

$\mu = 12.1\\\sigma = 0.3$

a) Find the probability that the drink is less than 11.9 fluid ounces

We are supposed to find P(x<11.9)

x= 11.9

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{11.9-12.1}{0.3}$

$z=-0.67$

Refer the z table

So, P(z<-0.67) = 0.2514

Hence the probability that the drink is less than 11.9 fluid ounces is 0.2514

b)Find the probability that the drink is between 11.6 and 11.9 fluid ounces

x= 11.6

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{11.6-12.1}{0.3}$

$z=-1.67$

x= 11.9

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{11.9-12.1}{0.3}$

$z=-0.67$

We are supposed to find P(11.6<x<11.9)

So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

Refer the z table

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

P(-1.67<z<-0.67)= 0.2514-0.0475

P(-1.67<z<-0.67)= 0.2039

So, the probability that the drink is between 11.6 and 11.9 fluid ounces is 0.2039.

c)Find the probability that the drink is more than 12.6 fluid ounces

We are supposed to find P(x>12.6)

x= 12.6

We will use z score formula :

$z=\frac{x-\mu}{\sigma}$

$z=\frac{12.6-12.1}{0.3}$

$z=1.67$

Refer the z table

P(x>12.6)=1-P(x<12.6)

P(z>1.67)=1-P(z<1.67)

P(z>1.67)=1-0.9525

P(z>1.67)=0.0475

Hence the probability that the drink is more than 12.6 fluid ounces is 0.0475

d) Is the drink containing more than 12.6 fluid ounces an unusual event?

Since p value is less than alpha (0.05)

Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.

3 0

3 years ago