HEEELLPP is just one question!

Mathematics

1 answer:

defon2 years ago

3 0

Answer:

65°

Step-by-step explanation:

The missing angle is x°

tan x° = $\frac{opposite }{adjacent }$

tan x°= $\frac{850}{400}$

tan x° = 2.125

using a calculator:

tan^(-1)(2.125) =64.79 ≈65°

You might be interested in

What is the value of?<br> –4<br> –2<br> 2<br> 4

Oliga [24]

Answer:

2 is your answer.

Step-by-step explanation:

Simplify. Remember to follow PEMDAS. First solve the parenthesis, then multiply, and finally divide.

-8(17 - 12) = -8(5) = -40

-2(8 - (-2)) = -2(8 + 2) = -2(10) = -20

-40/-20 = 2

2 is your answer.

4 0

2 years ago

Read 2 more answers

The half-life of a certain tranquilizer in the bloodstream is 22 hours. How long will it take for the drug to decay to 90% of

nasty-shy [4]

Answer:

It will take approximately 3.34 hours for the drug to decay to 90% of the original dosage

Step-by-step explanation:

As suggested, we use the formula for exponential decay:

$A(t)=A_0\,e^{-k\,t}$

From the given information, the half life of the drug in blood id 22 hours, so that means that it takes that number of hours to go from the initial value $A_0$ , to a final value equal to $A_0/2$ . Using this information we can find the decay rate "k" by solving for this parameter in the formula, and using the natural log function to bring the exponent down:

$A(t)=A_0\,e^{-k\,t}\\\frac{A_0}{2} =A_0\,e^{-k\,*22}\\\frac{A_0}{A_0*2} =e^{-k\,*22}\\\frac{1}{2} =e^{-k\,*22}\\ln(\frac{1}{2})=-k\,*22\\ k=-\frac{ln(\frac{1}{2})}{22} \\k=0.0315$

Now we use this value for the decay rate "k" to calculate how long it would take to decay to 90% of the original dose;

$A(t)=A_0\,e^{-0.0315\,t}\\0.9*A_0} =A_0\,e^{-0.0315\,t}\\\frac{0.9*A_0}{A_0} =e^{-0.0315\,t}\\0.9 =e^{-0.0315\,t}\\ln(0.9)=-0.0315\,t\\ t=-\frac{ln(0.9)}{0.0315} \\t=3.3447\,hours$