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Nookie1986 [14]
3 years ago
10

म़ीरा ने किस को अपऩी जाग़ीर बताया है?class 10​

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0

Answer:

कृष्ण‌ को marks as brain list

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The line that is perpendicular to y = -x and passes through the point (2, 4) is y = x
borishaifa [10]

Answer:

No

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Work out<br> 5(-2) x 327<br> Give your answer as a decimal.
GarryVolchara [31]
Answer: 0.12

5^-2=0.04
the cube root of 27=3
0.04x3=0.12
6 0
3 years ago
Kayla went over the allotted cell phone minutes this month by 42 minutes. Her regular bill is $39.95, but this month is was $54.
Nimfa-mama [501]

\frac{\text{ over time minutes }}{\text{ cost for overtime minute}} = \frac{42}{14.7}

The ratio of overtime minutes to the cost of those minutes is 42 : 14.7

<em><u>Solution:</u></em>

Kayla went over the allotted cell phone minutes this month by 42 minutes

Therefore,

over time minutes = 42 minutes

Her regular bill is $39.95, but this month is was $54.65

Regular bill = $ 39.95

This month bill = $ 54.65

<em><u>Therefore, cost for overtime minute is given by:</u></em>

cost for overtime minute = This month bill - regular bill

cost for overtime minute = $ 54.65 - $ 39.95

cost for overtime minute = 14.7

<em><u>Thus ratio of over time minutes to cost of those minutes is given by:</u></em>

\frac{\text{ over time minutes }}{\text{ cost for overtime minute}} = \frac{42}{14.7}

Thus the required ratio is found

8 0
4 years ago
Several years​ ago, 50​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1095, \pi = \frac{478}{1095} = 0.4365

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

5 0
3 years ago
While Diane was visiting her sister in Kingwood, she bought a bunch of balloons that was marked down 20% from an original price
shepuryov [24]

Answer:

$4.34

Step-by-step explanation:

Given the information:

  • The original price: $5
  • Discount : 20%
  • Tax: 8.5%

We can find out the actual price that Diane bought a bunch of balloons that was marked down 20% is:

= the original price (100% - discount rate)

= 5(100% -20%)

= $4

  • The tax amount she need to pay is:

= The actual price*tax rate

= $4*8.5%

= $0.34

=> the total cost of the bunch of balloons :

The actual price + tax price

= $4 + $0.34

= $4.34

Hope it will find you well.

4 0
3 years ago
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