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vova2212 [387]
2 years ago
15

A small truck can carry no more than 1600 pounds of cargo or 210 cubic feet of cargo. A printer weighs 20 pounds and occupies 3

cubic feet of space. A microwave oven weighs 30 pounds and occupies 2 cubic feet of space. Complete parts (a) and (b) below. (a) Using x to represent the number of microwave ovens and y to represent the number of printers, write a system of linear inequalities that describes the number of ovens and printers that can be hauled by the truck. y 2 3x + 2y s
Mathematics
1 answer:
elena55 [62]2 years ago
3 0

Answer:

Step-by-step explanation:

Given that a small truck can carry no more than 1600 pounds of cargo or 210 cubic feet of cargo.

A printer weighs 20 pounds and occupies 3 cubic feet of space.

A microwave oven weighs 30 pounds and occupies 2 cubic feet of space.

Let P be the no of printers and M microwave ovens.

Then the constraints are:

Total weight

=20P+30M\leq 1600

Total volume =

3P+2M\leq 210

These are the system of linear inequalities  that describes the number of ovens and printers that can be hauled by the truck.

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Answer:

x = 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

-2(x - 4) = -16

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -2:                    -2x + 8 = -16
  2. Isolate <em>x</em> term:                  -2x = -24
  3. Isolate <em>x</em>:                           x = 12

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    -2(12 - 4) = -16
  2. Subtract:                       -2(8) = -16
  3. Multiply:                        -16 = -16

Here we see that -16 does indeed equal -16.

∴ x = 12 is a solution of the equation.

6 0
2 years ago
Can you help me find the answer to it pls and ty &lt;3 .
grin007 [14]

The expression that represent the area of the cut off part is 81π / 4

<h3>How to find area?</h3>

The area of the cut off part can be found as follows:

Area of a circle = πr²

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Therefore, the cut off part is like 1 / 4th of a circle.

Hence,

area of the cut off region = πr² / 4

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area of the cut off region =  π9² / 4

area of the cut off region = 81π / 4

learn more on area here: brainly.com/question/15403474

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Heya!

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Step-by-step explanation:

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