If the area of a circle is 16π, the circumference of the circle is:
1 answer:
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Answer:
Step-by-step explanation:
{y = 6x − 11
{y = x² + 4x − 10
x² + 4x − 10 = 6x − 11
- [6x − 11] - [6x − 11]
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x² - 2x + 1
1 = x [Plug this back into both equations above to get the y-coordinate of −5]; −5 = y
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(a) For dx/dt=6, dy/dt = 2·6 = 12
(b) For dy/dt=2, 2 = 2·dx/dt ⇒ dx/dt = 1
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The value of x is irrelevant for this question.
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If your function is 2^x +1 or 2^(x +1), it needs to be written as such. The answer above applies to the function given.