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horrorfan [7]
4 years ago
12

A researcher wants to show the effects of slight changes in pH on the reproductive rates of fish in a lake. Why would a table be

more suitable than a graph to show the data?
a. Tables better illustrate precise data points.
b. Tables have data points with more significant figures.
c. Tables better illustrate the comparison of two different data sets.
d. Tables are better suited for displaying real-world data.
Chemistry
2 answers:
devlian [24]4 years ago
8 0

Answer:

The Answer is A

Explanation:

PIT_PIT [208]4 years ago
6 0

An initial decision that has to be made about your data is whether it should be displayed in a table or a graph. Though there are no hard rules, there are general guidelines you can use to make this determination. Tables better illustrates precise data points especially in slight changes.

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What mass in grams of MgSO4 is required to make 59.3 mL of 2.68 M<br> solution?
love history [14]

Answer:

Approximately 19.1\; \rm g.

Explanation:

<h3>Number of moles of formula units of magnesium sulfate required to make the solution</h3>

The unit of concentration in this question is "\rm M". That's equivalent to "\rm mol \cdot L^{-1}" (moles per liter.) In other words:

c(\mathrm{MgSO_4}) = 2.68\; \rm M = 2.68\; \rm mol \cdot L^{-1}.

However, the unit of the volume of this solution is in milliliters. Convert that unit to liters:

\displaystyle V = 59.3\; \rm mL = 59.3 \; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.0593\; \rm L.

Calculate the number of moles of \rm MgSO_4 formula units required to make this solution:

\begin{aligned}n(\rm MgSO_4) &= c \cdot V \\ &= 2.68 \; \rm mol \cdot L^{-1} \times 0.0593\; \rm L \approx 0.159\; \rm mol \end{aligned}.

<h3>Mass of magnesium sulfate in the solution</h3>

Look up the relative atomic mass data of \rm Mg, \rm S, and \rm O on a modern periodic table:

  • \rm Mg: 24.305.
  • \rm S: \rm 32.06.
  • \rm O: 15.999.

Calculate the formula mass of \rm MgSO_4 using these values:

M(\mathrm{MgSO_4}) = 24.305 + 32.06 + 4 \times 15.999 \approx 120.361\; \rm g \cdot mol^{-1}.

Using this formula mass, calculate the mass of that (approximately) 0.159\; \rm mol of \rm MgSO_4 formula units:

\begin{aligned}m(\mathrm{MgSO_4}) &= n \cdot M \\&\approx 0.159 \; \rm mol \times 120.361 \; \rm g \cdot mol^{-1} \approx 19.1\; \rm g\end{aligned}.

Therefore, the mass of \rm MgSO_4 required to make this solution would be approximately 19.1\; \rm g.

3 0
3 years ago
In the spring of 1984, concern arose over the presence of ethylene dibromide, or EDB, in grains and cereals. EDB has the molecul
Lady bird [3.3K]

869.6 × 10¹⁴ molecules of EDB

Explanation:

We have 1.9 lb of flour with a EDB concentration of 31.5 ppb.

We need to transform lb in grams.

1 lb = 453.6 grams

1.9 lb = (1.9 × 453.6) / 1 = 861.8 grams

Now we determine the number of molecules of EDB in the sample by devise the following reasoning:

if we have        31.5 × 10⁻⁹ g of EDB in 1 g of sample

then we have   X  g of EDB in 861.8 g of sample

X = (31.5 × 10⁻⁹ × 861.8) / 1 = 27146.7 × 10⁻⁹ g of EDB

Molecular mass of EDB (C₂H₄Br₂) = 188 g/mole

Taking in account that 1 mole of any substance contains 6.022 × 10²³ (Avogadro’s number) molecules we devise the following reasoning:

if       188 g of EDB contains 6.022 × 10²³ molecules

then 27146.7 × 10⁻⁹ g of EDB contains Y molecules

Y = (27146.7 × 10⁻⁹ × 6.022 × 10²³) / 188 = 869.6 × 10¹⁴ molecules of EDB

Learn more:

about Avogadro’s number

brainly.com/question/1445383

#learnwithBrainly

8 0
4 years ago
Read 2 more answers
What happens when the electron moves from the first energy level to the second energy level?
Flura [38]
The electron would absorb a quantum of energy
3 0
4 years ago
Be sure to answer all parts. What can be added to the equilibrium AgCl(s) + 2NH3(aq) ⇌ Ag(NH3)2+(aq) + Cl−(aq) (a) that will shi
lora16 [44]

Answer:

a) Ag(NH₃)₂⁺,  Cl⁻.

b) NH₃.

c) AgCl.

Explanation:

Based on LeChatelier's law, a system in chemistry can change responding to a disturbance of concentration, temperature, etc. in order to restore a new state.

In the reaction:

AgCl(s) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)

When reactants are added, the system will produce more products restoring the equilibrium and vice versa. A reactant in solid state doesn't take part in the equilibrium, thus:

a) Ag(NH₃)₂⁺,  Cl⁻. The addition of products will shift the equilibrium to the left

b) NH₃. The addition of reactant will shift the equilibrium to the right.

c) As AgCl is in solid phase, will not shift the equilibrium in either direction.

6 0
3 years ago
A dosage is prescribed as 4.00 mg of medicine per kg of body weight.What dose should be given to a 112 pound person
vodka [1.7K]

Answer:

203.64 mg

Explanation:

112/2.2= 50.91

50.91x4.00= 203.64

4 0
4 years ago
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