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spin [16.1K]
3 years ago
7

A dosage is prescribed as 4.00 mg of medicine per kg of body weight.What dose should be given to a 112 pound person

Chemistry
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

203.64 mg

Explanation:

112/2.2= 50.91

50.91x4.00= 203.64

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There are many compounds that contribute to the overall aroma of a banana. The primary compound is called isoamyl acetate and co
Murljashka [212]

Explanation:

Let the mass of isoamyl acetate be 100g.

Moles of Carbon = 60.58/12 = 5.048mol

Moles of Hydrogen = 7.07/1 = 7.07mol

Moles of Oxygen = 32.28/16 = 2.018mol

Mole Ratio of C : H : O

= 5.048 : 7.07 : 2.018

= 5 : 7 : 2.

Hence the empirical formula of isoamyl acetate is C5H7O2.

8 0
3 years ago
10. In which of the following is the symbol for the ion and the total number of electrons it contains given correctly?
dalvyx [7]

Answer:

10. D

9. A

8. A or B

Explanation:

10. Calcium has 20 electrons, but the Calcium ion has 18 electrons.

9. The mass of electrons are negligible.

8. Electrons have a very small mass where some consider it to have no mass.

5 0
3 years ago
What happens when an electron jumps energy from energy level 3 energy level 6 in an atom
Alik [6]

Explanation:

high energy to Low energy

=the electron gains energy (K.E)

4 0
2 years ago
3. How many moles are 1.707 x 10^24 atoms of carbon?
Paraphin [41]

Answer:

2.835 moles of carbon

Explanation:

By definition, there are 6.022x10^23 atoms (or compounds) in one mole.

Write and use this as a conversion factor:

(6.022x10^23 atoms)/mole

(1.707 x 10^24 atoms of carbon)/((6.022x10^23 atoms)/mole) = 2.835 moles carbon

8 0
2 years ago
What is the percent by mass of nahco3 in a solution containing 10 g of nahco3 dissolved in 400 ml of h2o?
Marat540 [252]
Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
7 0
3 years ago
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