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2 years ago

A 6.0 M HCl solution is available. What volume is needed to make 6.00 L of 1.00 M solution?

Chemistry

1 answer:

Ket [755]2 years ago

5 0

Answer:

The volume of the stock solution needed is 1L

Explanation:

Step 1:

Data obtained from the question. This include the following:

Concentration of stock solution (C1) = 6M

Volume of stock solution needed (V1) =?

Concentration of diluted solution (C2) = 1M

Volume of diluted solution (V2) = 6L

Step 2:

Determination of the volume of the stock solution needed.

With the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

C1V1 = C2V2

6 x V1 = 1 x 6

Divide both side by 6

V1 = 6/6

V1 = 1L

Therefore, the volume of the stock solution needed is 1L

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Answer:

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Explanation:

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Using integrated rate law for first order kinetics as:

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Where,

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$[A_0]$ is the initial concentration

Given that:

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Final concentration $[A_t]$ = 91 kPa

Time = ?

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$91=125e^{-2.8\times 10^{-3}\times t}$

$125e^{-2.8\times \:10^{-3}t}=91$

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