First, calculate the amount fo Na2O that should be produced with the given amount of sodium using proper dimensional analysis and the balanced chemical reaction,
theoretical amount of Na2O = (54.1 g of Na)(1 mol Na/23 g Na)(2 mos Na2O/4 mols Na)(62 g Na2O/ 1mol Na2O)
theoretical amount of Na2O = 72.9 g of Na2O
Calculation of percent yield,
% yield = (61.8 g Na2O) / (72.9 g of Na2O) x 100%
% yield = 84.75%
Answer: 84.75%
Answer:
[H⁺] = 3.02 x 10⁻¹⁰M
Explanation:
Given parameters:
pH of the solution = 9.52
Unknown:
Concentration of the solution
Solution
There is a relationship between the pH and concentration of a solution.
pH = -log₁₀[H⁺]
The unknown here is [H⁺],
Now making it the subject of the formula
[H⁺] = Inverse log₁₀(-pH)
[H⁺] = Inverse log₁₀(-9.52)
[H⁺] = 3.02 x 10⁻¹⁰M
= 
= 9.95 mL
x 100 
x 100 = 0.5 % error