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Alchen [17]
3 years ago
10

An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d = 13.53 g/cm3). What i its volu

me? (b) How much would the vial weigh if it were filled with water (d= 0.997 g/cm3 at 25°C)?
Chemistry
1 answer:
Tasya [4]3 years ago
3 0

Answer:

a) Volume of vial= 9.626cm3

b) Mass of vial with water = 62.92 g

Explanation:

a) Mass of empty vial = 55.32 g

Mass of Vial + Hg = 185.56 g

Therefore,

mass\ of\ Hg = 185.56-55.32 = 130.24 g

Density of Hg = 13.53 g/cm3

Volume\ of\ vial = Volume\ of\ Hg = \frac{Mass}{Density} \\\\= \frac{130.24g}{13.53g/cm3} = 9.626 cm3

b) Volume of water = volume of vial = 9.626 cm3

Density of water = 0.997 g/cm3

Mass\ of\ water = Density*volume = 0.997g/cm3*9.626cm3=9.60 g\\\\Total\ Mass\ of\ vial = Empty\ vial + mass\ of\ water\\= 53.32+9.60= 62.92g

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This is the complete question with grammar corrections:

A glass vessel calibrated to contain 9.76 mL at 4° C was found to weigh 22.624 g when empty and dry. Filled with a soduim chloride (NaCl) solution at the same temperature , it was found to weigh 32.770 g. Calculate the solution's density.

Answer:

<u></u>

  • <u>1.04 g/ml</u>

Explanation:

<em>Density</em> is the physical property that expresses the amount of matter (mass) per voumetric unit of solution:

  • Density = mass / volume.

In this problem, you can first calculate the mass, by difference. After that, you just have to divide the mass by the volume of the glass vessel (9.76 ml as per the calibration).

This is the two steps procedure.

<u>1. Mass of the solution:</u>

  • Mass of solution = mass of the vessel filled with the solution - mass of the vessel, empty and dry

       Mass of solution = 32.770 g - 22.624 g = 10.146 g

<u>2. </u><em><u>Solution's density</u></em><u>:</u>

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