Answer:
1 .
2.
Explanation:
The more stable the ionic compound, the more is it lattice energy.
- The more the charge on the cation and the anion, the greater is the lattice energy.
- The less the size of the cation and the anion, the greater is the lattice energy.
Scandium oxide () is an oxide in which behaves as cation and behaves as anion.
The compounds which has higher lattice energy than scandium oxide are:
1 .
This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation is smaller than . Thus, this corresponds to higher lattice energy.
2.
This is because the charge on the cation is greater than that of and also the size of the cation is smaller than . Thus, this corresponds to higher lattice energy.
Molar mass :
NaBr = 103 g/mol
Pb(NO3)2 = 331.20 g/mol
<span><span /><span>Balanced chemical equation :
</span></span>2 NaBr + 1 Pb(NO3)2 = 2 NaNO3 + 1 PbBr<span>2
</span><span>
2*103 g NaBr ------------> 1 * 331.20 g Pb(NO3)2
g NaBr -------------------> 311 g Pb(NO3)2
331.20 g = 2*103*311
331.20 g = 64066
mass ( NaBr ) = 64066 / 331.20
mass ( naBr) = 193,43 g of NaBr
hope this helps!.
</span>
Answer:
9.35g
Explanation:
The molarity equation establishes that:
So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:
The mathematical equation that establishes the relationship between molar weight, mass and moles is:
We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem: