Answer:
80000 square meters
Step-by-step explanation:
perimeter + dividing fence = 800
let a = length
let b = width
let c = length of dividing fence
perimeter = 2*a + 2*b
let's say...
c is the same as the length
2a + 2b + c = 800
2a + 2b + a = 800
3a + 2b = 800
area = length*width
area = a*b
area / b = a
3*(area/b) + 2b = 800
3*(area/b) = 800 - 2b
area/b = (800 - 2b)
area = (800 - 2b)*b
To make the area large, we make the right hand side large.
800b - 2b^2
If you put in terms of x, y it looks like a downward opening parabola, so the max area is at the vertex. Half way between the roots.
y = -2x^2 + 800x
y = -x^2 + 400x
0 = x*(-x + 400)
roots are x= 0 and x = 400
vertex is at x, aka b = 200
area at b=200 is (800 - 400)*200 = 80000
and a is area/b... 80000/400 = 200
Answer:
25
Step-by-step explanation:
When we write expressions for the total cost of each field visit and set them equal, we find the solution to be the ratio of the difference in fixed cost to the difference in variable cost.
y = 75 +7x . . . . . cost for x students to visit the science center
y = 50 +8x . . . . cost for x students to visit the natural history museum
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Subtracting the first equation from the second, we get ...
0 = -25 +x
25 = x . . . . . add 25; the number of students such that costs are equal
The cost will be the same either place for 25 students.
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<em>Additional comment</em>
Here, the fixed cost difference is 75-50=25, and the variable cost difference is 8-7=1. The ratio of these costs is ...
$25/($1 /student) = 25 students.
This relationship only holds when the higher fixed cost is associated with the lower variable cost. Charges are such that one place caters to larger numbers of students (science center), and one prefers fewer students (natural history museum).
Hello, you would divide 10.3 by 0.6 to get 17.166 repeating. So y equals 17.166.
Answer:b
Step-by-step explanation:it equals out to 180°
Answer:
35/8
Step-by-step explanation:
4×8= 32 plus the 3/8 equals 35/8
hope it helps
