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Nitella [24]
2 years ago
10

5.5 x 10^-8 in standard form

Mathematics
1 answer:
dangina [55]2 years ago
3 0

Step-by-step explanation:

0.000000055

hope it helps you

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Write an expression to represent . Eight less than the product of two and a number x
kvv77 [185]
The answer is 2x-8 where “the product of two and a number” is the 2x and 8 less is to subtract 8 from the 2x so your answer is 2x-8
5 0
3 years ago
Find the minimum or maximum value of the function g(x)=−3x2−6x+5
polet [3.4K]

Step-by-step explanation:

g(x) = ax²+bx+c

g(x)=−3x²−6x+5

a = -3, b= -6, c = 5

since a <0 , the function has only maximum value.

=> g'(x) = 0

-6x -6 = 0

-6x = 6

x = -1

the maximum value => g(-1) =

-3(-1)²-6(-1)+5 = -3+6+5 = 9

the domain : {x | x € Real numbers}

the range : {y| y ≤ 9, y € Real numbers}

the function is increasing for x < -1

the function is decreasing for x > -1

4 0
3 years ago
Test the four possible vertices that you found in the objective function in part A. Use those values to determine which set of v
irga5000 [103]

The testing of the four vertices of the objective function gives;

C(5, 0, 55) = 430

C(5, 30, 25) = 400

C(15, 30, 15) = 420

C(45, 0, 15) = 510 (maximum)

<h3>How to test objective functions?</h3>

The objective function is seen as attached.

Now, it is noticed that just two of the vertices are listed. The other two vertices are intersections of x + y + z = 60 with x = 5 and the constraints on y.

We will assume that; 0 ≤ y ≤ 30

Thus, the missing vertices are;

(x, y, z) = (5, 0, 55)  and  (5, 30, 25)

The two given vertices are;

(x, y, z) = (15, 30, 15)  and  (45, 0, 15)

Therefore, the objective function values are;

C(5, 0, 55) = 9·5 +6·0 +7·55 = 45 +0 +385 = 430

C(5, 30, 25) = 9·5 +6·30 +7·25 = 45 +180 +175 = 400

C(15, 30, 15) = 9·15 +6·30 +7·15 = 135 +180 +105 = 420

C(45, 0, 15) = 9·45 +6·0 +7·15 = 405 +0 +105 = 510

Read more about Objective Functions at; brainly.com/question/16826001

#SPJ1

5 0
1 year ago
NEED THESE ANSWERED ASAP SO I CAN GRADUATE THIS WEEK
babunello [35]

For this case we must solve each of the equations proposed:

A) -6 (2s-1) = 30

We apply distributive property to the terms within parentheses:

-12s + 6 = 30

Subtracting 6 from both sides of the equation we have:

-12s = 24

Dividing between -12 on both sides of the equation:

s = \frac {24} {- 12}s = -2

B) -3m = -5 (m-8)

We apply distributive property to the terms within parentheses:

-3m = -5m + 40

We add 5m on both sides of the equation:

2m = 40

Dividing between 2 on both sides of the equation:

m = \frac {40} {2}\\m = 20

C) 7 (2-g) = 49

We apply distributive property to the terms within parentheses:

14-7g = 49

We subtract 14 from both sides of the equation:

-7g = 35

Dividing between -7 on both sides of the equation:

g = \frac {35} {- 7}\\g = -5

D) -7 (3w + 4) = 14

We apply distributive property to the terms within parentheses:

-21w-28 = 14

We add 28 to both sides of the equation:

-21w = 42

Dividing between -21 on both sides of the equation:

w = \frac {42} {- 21}\\w = -2

Answer:

s = -2\\m = 20\\g = -5\\w = -2

6 0
3 years ago
Read 2 more answers
Consider the function p(c)=2^c+1 . What is p(3)? 8 6 9 -8
Brilliant_brown [7]

Answer:

im gonna say its 6 but im not so sure. But thats my closest answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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