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andreev551 [17]
3 years ago
11

What is the quotient in simplest form? 8 Over 3 divided by two-thirds

Mathematics
1 answer:
Darina [25.2K]3 years ago
7 0

Answer:

4

Step-by-step explanation:

8/3 ÷ 2/3

8/3 * 3/2

4

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Hello I need help<br> Find the missing side lengths, leave your answers as radicals in simplest form
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y =  \frac{1}{2}  \times  \frac{8 \sqrt{3} }{3}  \\

y = \frac{4 \sqrt{3} }{3}  \\

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x =  \frac{ \sqrt{3} }{2}  \times  \frac{8 \sqrt{3} }{3}  \\

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x = 4

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4 0
3 years ago
find all the solutions of sec theta - 2 =0. It says use "or" as necessary and gives an example of kpi.
swat32
Sec t (theta) - 2 = 0
sec t = 2
1/ cos t = 2
cos t =  1/2
Answer:
t = π / 3 + 2 k π ,  or :  t = 5 π / 3 + 2 kπ,
k ∈ Z
5 0
3 years ago
State the degree x^3y^2+7x^2y^5-3xy^8
KATRIN_1 [288]
The main formula for a polynomial ax^my^n+...
the degree is the sum of the highest degree of the polynomial, it is m+n

<span>the degree of  x^3y^2+7x^2y^5-3xy^8 is 9, because </span><span>3xy^8 is the term where we can find a highest value of power (8)
so the degree is degree of x, it is 1 + degree of y (it is 8)
</span>
4 0
3 years ago
Read 2 more answers
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
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