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vodka [1.7K]
3 years ago
10

ILL GIVE YOU BRAINLIST !!! HAVE TO GET IT RIGHT !!

Chemistry
1 answer:
inysia [295]3 years ago
4 0

Answer: The 3rd and 6th bullet point is the quantitative data.

Explanation: Quantitative data is expressed by NUMBERS and Qualitative data is expressed by WORDS. The 3rd and 6th one is correct because they both use numbers to compare how much time hummingbirds spent feeding on nectar.  

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Pizza is an example of a homogeneous mixture.
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No its a example of heterogeneous mixture
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the formula for solid Cobalt II chloride is CoCl2 6H2O. what is the name given to compounds such as this, which have water as pa
ser-zykov [4K]
<span>This type of salt is called a hydrated salt. This specific salt is called Cobalt (II) chloride hexahydrate. Hydrated salts is a salt has a number of water molecules associated with the ions in its crystalline structure.</span>
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3 years ago
The picture below shows a flower experiencing phototropism, a type of growth movement.
lakkis [162]
The correct answer is A
4 0
2 years ago
Read 2 more answers
In the reaction: C6H6 + O2 = CO2 + H2O If 26.2 grams of C6H6 is reacted in a 0.250-liter container and this reaction is carried
Lelechka [254]
<h3>Answer:</h3>

43.33 atm

<h3>Explanation:</h3>

We are given;

Mass of C₆H₆ = 26.2 g

Volume of the container = 0.25 L

Temperature = 395 K

We are required to calculate the pressure inside the container;

First, we calculate the number of moles of C₆H₆

Molar mass of C₆H₆ =  78.1118 g/mol.

But; Moles = mass ÷ Molar mass

Moles of  C₆H₆ = 26.2 g ÷  78.1118 g/mol.

                         = 0.335 moles C₆H₆

Second, we calculate the pressure, using the ideal gas equation;

Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore;

P = nRT ÷ V

  = (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L

 = 43.433 atm

Therefore, the pressure inside the container is 43.33 atm

6 0
3 years ago
At the beginning of the shift at 7:00 am, a client has 650 ml of normal saline solution left in the intravenous bag, which is in
madreJ [45]

The 8 hour shift is from 7.00 am to 3.00 pm.<span>
<span>At the beginning, from 7.00 am to 9.30am (2.5 hrs.),<span> the client has normal saline which </span></span>is infusing at 125 ml/hr.
Hence amount of normal saline which was injected= 2.5 hrs. x 125 ml/hr.
                                                                                 = 312.5 ml
from 9.30am to 3.00 pm (5.5 hrs) lactated ringer solution, which is to infuse at 100 ml/hr was given. 
Hence amount of lactated ringer solution given = 5.5 hrs x 100 ml/hr
                                                                           = 550 ml
Total amount of IV solution given = normal saline + lactated ringer solution
                                                     = 312.5 ml + 550 ml
                                                     = 862.5 ml
<span>                                                     = 863 ml</span></span>

5 0
3 years ago
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