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vodka [1.7K]
3 years ago
10

ILL GIVE YOU BRAINLIST !!! HAVE TO GET IT RIGHT !!

Chemistry
1 answer:
inysia [295]3 years ago
4 0

Answer: The 3rd and 6th bullet point is the quantitative data.

Explanation: Quantitative data is expressed by NUMBERS and Qualitative data is expressed by WORDS. The 3rd and 6th one is correct because they both use numbers to compare how much time hummingbirds spent feeding on nectar.  

You might be interested in
What is it called when moon is between setting and rising
miv72 [106K]

Answer:

I hope this link helps you.

Explanation:

http://astronomy.swin.edu.au/cosmos/P/Phases

4 0
3 years ago
Write a balanced equation for the complete combustion of solid palmitic acid. Remember that oxygen (O2(g)) is necessary for the
Alina [70]

Answer:

C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)

Explanation:

In order to determine a combustion reaction we should know that:

Reactants are: X compound and O₂

Products are: CO₂ and H₂O

In this case, the X compound is the solid palmitic acid: C₁₆H₃₂O₂

The balanced equation will be:

C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)

3 0
2 years ago
What is the charge of phosphate in AlPO4?
Dennis_Churaev [7]

The charge of phosphate : 3-

<h3>Further explanation</h3>

Oxidation is an increase in oxidation number, while reduction is a reduction in oxidation number.

The formula for determining Oxidation Numbers in general:

1. Single element atomic oxidation number = 0.

Group IA (Li, Na, K, Rb, Cs, and Fr): +1

Group IIA (Be, Mg, Ca, Sr and Ba): +2

Group IIIA(Al, B) : +3

H in compound = +1, except metal hydride compounds (Hydrogen which binds to groups IA or IIA) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in an uncharged compound = 0,

Total oxidation number in ion = ion charge, Example NO₃⁻ = -1

Compound AlPO₄ :

The oxidation number in an uncharged compound = 0

Since the charge of Al as group 3A (or group 13) is +3, while the AlPO₄ compound is a polyatomic compound (consisting of polyatomic ions PO₄ and Al), the PO₄ charge:

charge Al + charge PO₄ = 0

+ 3 + charge PO₄ = 0

<em>charge PO₄ = -3</em>

6 0
2 years ago
Which of the following is an example of a chernical change?
matrenka [14]

Answer:

the chemical change occur in burning paper.

boiling water does not make any chemical change

melting gold "

dissolving sugar in water "

in these examples the reactant remains as the same , even if you melt gold it is gold itself, it only change its state.

7 0
3 years ago
Read 2 more answers
A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 198 picometers and its
Neko [114]

Answer:

7.38 g/cm³ is the density of the metal

Explanation:

In a Face-centered cubic unit cell you have 4 atoms. Also, the edge length is √8×r (r is radius of the atom).

To solve this problem, we need first to calculate the volume of the unit cell and then, with molar mass calculate the mass of 4 atoms. As density is the ratio between mass and volume we can obtain this value.

  • <em>Volume of the unit cell</em>

Volume = a³

a = √8×r

(r = 198x10⁻¹²m)

a = 5.6x10⁻¹⁰ m

Volume = 1.756x10⁻²⁸ m³

1m = 100cm → 1m³ = (100cm)³:

1.756x10⁻²⁸ m³× ((100cm)³ / 1m³) =

<h3> 1.756x10⁻²² cm³ → Volume of the unit cell in cm³</h3><h3 />
  • <em>Mass of the unit cell:</em>

<em>There are 4 atoms of gold:</em>

4 atoms × (1mol / 6.022x10²³ atoms) = 6.64x10⁻²⁴ moles of gold

As 1 mole weighs 195.08g:

6.64x10⁻²⁴ moles of gold × (195.08g / mol) =

<h3>1.296x10⁻²¹g is the mass of the unit cell</h3><h3 />
  • <em>Density of the metal:</em>

1.296x10⁻²¹g / 1.756x10⁻²² cm³ =

<h3>7.38 g/cm³ is the density of the metal</h3>
3 0
2 years ago
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