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Crank
3 years ago
5

What is the factor in deterring the average atomic mass of an element

Chemistry
1 answer:
frozen [14]3 years ago
3 0
Hope this helps! I found it when I searched your question.

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How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?
allochka39001 [22]

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

 

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

 

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

 

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

<span>volume Na2S = 0.0212 L = 21.2 mL</span>

6 0
3 years ago
What is the volume of 0.250 m hydrochloric acid required to react completely with 20.0 ml of 0.250 m ca(oh)2?
Soloha48 [4]
The balanced equation for the above neutralisation reaction is as follows;
Ca(OH)₂ + 2HCl ----> CaCl₂ + 2H₂O
Stoichiometry of Ca(OH)₂ to HCl is 1:2
number of Ca(OH)₂ moles reacted - 0.250 mol/L x 20.0 x 10⁻³ L = 5.00 x 10⁻³ mol
according to molar ratio of 1:2
number of HCl moles required = 2 x number of Ca(OH)₂ moles reacted
number of HCl moles = 5.00 x 10⁻³ x 2 = 10.0 x 10⁻³ mol
molarity of HCl solution - 0.250 M
there are 0.250 mol  in volume of 1 L
therefore 10.0 x 10⁻³ mol in - 10.0 x 10⁻³ mol  / 0.250 mol/L = 40.0 mL 
40.0 mL of 0.250 M HCl is required
5 0
3 years ago
What is the mole ratio to correct balance the reaction below? __KBr + __Ca3N2--&gt; __CaBr2 + __K3N
jonny [76]

Explanation:

3CaBr2 + 2K3N → 6KBr + Ca3N2

7 0
3 years ago
Consider the reaction X + Z ?
lions [1.4K]

Answer:

X2Z3

Explanation:

Based on the clues, X is a metal and Z is a non-metal.

X could be aluminum and Z would need to be an element from the oxygen family.

8 0
2 years ago
1. Es un
artcher [175]

Answer:

A ) MOVIMIENTO

Explanation:

PLEASE MARK ME AS BRAINLIEST

7 0
2 years ago
Read 2 more answers
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