Answer:
11.0 dm³
Explanation:
From the question,
Applying
PV= nRT............... Equation 1
Where P = pressure of oxygen gas, V = volume of oxygen gas, n = number of moles of oxygen, R = molar constant, T = Temperature.
make V the subeject of the equation
V = nRT/P............. Equation 2
But,
Number of mole (n) = Mass of oxygen(m)/Molar mass of oxygen(m')
n = m/m'....................... Equation 3
Substitute equation 3 into equation 2
V = mRT/Pm'............. Equation 4
Given: T = 28°C = (28+273) = 301 K, P = 0.998 torr = (0.998×0.00131579) = 1.3132 atm, m = 18.4 g
Constant: R = 0.082 atm.dm³/K.mol, m' = 32 g/mol.
Substitute these values into equation 4
V = (301×18.4×0.082)/(32×1.3132)
V = 454.1488/42.0224
V = 10.81 dm³
V = 11.0 dm³
