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3 years ago

In pea plants, yellow seeds are dominant to green seeds. A heterozygous yellow-

Chemistry

1 answer:

san4es73 [151]3 years ago

3 0

Answer:

The phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours

Explanation:

The crossing to determine the offsprings is shown in the image attached where we have two green (Yy) seeds and two yellow (yy) seeds as offsprings.

Thus, <u>the phenotypic percentage of having yellow or green seeds is 50% for having either of the two colours</u>.

Note, the dominant allele is "Y" while the recessive allele is "y". Thus, Yy would produce a yellow colour while yy would produce a green colour (as both mentioned in the question).

Also note that phenotype describes the outward properties/characteristics of an individual.

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Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.

Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= $moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.241}{0.0137kg}=17.6mole/kg$

Therefore, the molality of solution is 17.6 mole/kg

3 0

3 years ago

What do genotype will appear in boxes 2 and 3?

VMariaS [17]

Tt is the genotype that will appear in boxes two and three.

If you look at the column and row that intersect to form boxes two and three, you will see that they are T and t. That is the best way I can describe it, sorry if it’s confusing.

3 0

3 years ago

Read 2 more answers

Balancing chemical equations

kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

B: 2a + 0b = 2c

O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

a = 2

b = 3

c = 2

4. Substitute Coefficients and Verify Result

2B2 + 3O2 = 2B2O3

L R

B: 4 4 ✔️

O: 6 6 ✔️

hope this helps!

7 0

2 years ago

A student with an unknown code of Q3A conducts a qualitative analysis of her unknown. Her results indicated the formation of a y

insens350 [35]

Answer:

Grey precipitate implies the presence of silver ions

Yellow precipitate implies the presence of lead II ions

Explanation:

Qualitative analysis provides us a quick method of identifying ions present in a sample by chemical reactions involving simple reagents. Precipitates having a unique colour is formed. The identity of ions in the sample is deduced from the colour of precipitate obtained when particular reagents are added.

In the question, a precipitate containing silver ions upon standing turn into grey colour. Similarly, lead II ions give a yellow precipitate.

6 0

3 years ago

Which isomer of 1-bromo-4-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?

grigory [225]

Answer:

See explanation.

Explanation:

Since potassium tert-butoxide is a strong bulky base, we expect that an elimination reaction predominates.

This reaction is expected to occur by E2 mechanism. The cis isomer of 1-bromo-4-tert-butylcyclohexane is known to react faster by E2 mechanism because it fulfills the anticoplanar arrangement required for for E2 mechanism, where the leaving group and adjacent proton must be anti to each other and in the same plane. The trans isomer can not fulfill this requirement.

7 0

2 years ago