36 perches altogether.
I hope you like this answer, please Brainliest me, and have a great day! :D
I might be wrong but I say 16
Answer: Hello your question is incomplete attached below is the missing
n ( 1 + n )
Step-by-step explanation:
P( Bob hits target ) = 1/3
P( Eve hits target ) = 2/3
P( Carol hits target ) = 1
<u>Compute the P that Bob wins in a duel against Eve alone</u>
P(Bob hits the target in first shot ) = n = 1/3
P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9
hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )
Answer:
7020
Step-by-step explanation:
The letter could be any 1 of the 26 and it could be placed in any 1 of 3 places so this makes 26*3 = 78 possibilities.
For each of these there is any one of permutations of 2 digits from 10
= 10P2 = 10! / 8! = 10*9 = 90.
So the answer is 78 * 90 = 7020.
Note I am assuming that the 2 digits picked are different - no duplicates.
please mark me brainliest!
X= 3r+5/2 is the answer I believe