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11111nata11111 [884]

3 years ago

9

How does the graph of mc016-1.jpg compare to the graph of the parent square root function?The graph is a horizontal shift of the

parent function 2 units right.
The graph is a horizontal shift of the parent function 2 units left.
The graph is a vertical shift of the parent function 2 units up.
The graph is a vertical shift of the parent function 2 units down.

1 answer:

lions [1.4K]3 years ago

5 0

The standard graph of the parent square root function shifted or transformed 2 units up or positive on the y-axis. Thus, the graph is a vertical shift of the parent function 2 units up. You can conclude that because the “y” is on the left side which means the vertical shift.

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Match the vocabulary word to its correct definition.

Trava [24]

Answer:

1. Complex number.

2. Imaginary part of a complex number.

3. Real part of a complex number.

4. i

5. Multiplicative inverse.

6. Imaginary number.

7. Complex conjugate.

Step-by-step explanation:

1. <u><em>Complex number:</em></u> is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.

2. <u><em>Imaginary part of a complex number</em></u>: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.

3. <em><u>Real part of a complex number</u></em>: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.

4. <u><em>i:</em></u> a number defined with the property that 12 = -1.

5. <em><u>Multiplicative inverse</u></em>: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.

6. <em><u>Imaginary number</u></em>: any nonzero multiple of i; this is the same as the square root of any negative real number.

7. <em><u>Complex conjugate</u></em>: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.

4 0

3 years ago

What is 83 divided by 72,628 not as a dec͓̽i͓̽m͓̽a͓̽l͓̽ answer

Fiesta28 [93]

The answer is 5663588 for your question

4 0

3 years ago

A=bh; A=48, b=12 what is h equal?

OleMash [197]

1. Plug in numbers
•48=12h
2. Divide 48 by 12
•48/12=12h/12
3. 12/12 cancels out, and 48/12=4

h=4

5 0

3 years ago

Read 2 more answers

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em> $p(x)$ <em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em> $p(x)=x^4-9x^2-4x+12$ <em> and will solve the question based on this assumption expression of </em> $p(x)$ <em>, which anyways would solve your query.</em>

Answer:

As

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

As

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say<em> </em> $p(x)$ <em>, </em> $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ <em>, </em>we must have to evaluate <em> </em> $p(x)$ <em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0$

$\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=2^4-2^2\cdot \:9+8+12$

$=2^4+20-2^2\cdot \:9$

$=16+20-36$

$=0$

Thus,

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Now, solving for $p\left(2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12$

$p\left(2\right)=2^4-2^2\cdot \:9-8+12$

$p\left(2\right)=2^4+4-2^2\cdot \:9$

$p\left(2\right)=16+4-36$

$p\left(2\right)=-16$

Thus,

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Keywords: polynomial, root

Learn more about polynomial and root from brainly.com/question/8777476

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7 0

3 years ago

Read 2 more answers

Describe what solving a trigonometric equation is.

AleksAgata [21]

That's an awfully broad question. Could you not be more specific?

A basic example: Suppose you are told that sin theta = 1/2. Solving this equation would require finding the measure of the angle theta. In this case the answer would be "30 degrees," or "pi/6 radians."

6 0

3 years ago