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Genrish500 [490]
3 years ago
5

Using the IUPAC nomenclature rules and the periodic table choose the correct name for the following ionic compounds Al2O3

Chemistry
2 answers:
Brilliant_brown [7]3 years ago
8 0

Answer:

the first one is: aluminum oxide

the second one is: sodium sulfide

Explanation:

grigory [225]3 years ago
6 0

Answer:

Aluminum oxide

Explanation:

Just answered and was right

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Classify water as proton donor or proton acceptor with reactions???
olasank [31]

Answer: It should a accepter

Explanation: because water is often used as solvent for solutes...there are exceptions

4 0
3 years ago
A compound is formed when 9.03 g
NikAS [45]

The percent composition  of this compound :

Mg = 72.182%

N = 27.818%

<h3>Further explanation</h3>

Given

9.03 g  Mg

3.48 g  N

Required

The percent composition

Solution

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

Total mass of the compound :

= 9.03 g + 3.48 g

= 12.51 g

The percent composition :

Mg : 9.03/ 12.51 g x 100% = 72.182%

N : 3.48 / 12.51 g x 100% = 27.818%

3 0
3 years ago
If the Dry bulb reads 25 degrees Celsius and the wet bulb reads 22
Nitella [24]

Answer:

Relative humidity is low .

Explanation:

The wet bulb reads low temperature because due to low humidity of atmosphere , evaporation of water takes place from the wet bulb which makes the bulb cool and therefore it reads lower temperature . In the process of evaporation , heat equal to latent heat of vaporization is taken from the bulb and it loses temperature.

6 0
2 years ago
Mike mixes two chemicals in a container. The container quickly becomes very hot.
Kipish [7]
The chemicals are reactive with one another
7 0
2 years ago
Read 2 more answers
An industrial manufacturer wants to convert 175 kg of methane into HCN. Calculate the masses of ammonia and molecular oxygen req
Tema [17]
Given:

175 kilograms of Methane (CH4) to be synthesized into Hydrogen Cyanide (HCN)

The balanced chemical equation is shown below:

2 CH4<span> + 2 NH</span>3<span> + 3 O</span>2<span> → 2 HCN + 6 H</span>2<span>O
</span>
To calculate for the masses of ammonia and oxygen needed, our basis will be 175 kg CH4.

Molar mass:
CH4 = 16 kg/kmol
NH3 = 17 kg/kmol
O2 = 32 kg/kmol

mass of NH3 = 175 kg CH4 / 16 kg/kmol * (2/2) * 17 kg/kmol 
mass of NH3 = 185.94 kg NH3 needed

mass of O2 = 175 kg CH4 / 16 kg/kmol * (3/2) * 32 kg/kmol
mass of O2 = 525 kg

mass of O = 525 kg / 32 kg/kmol * (1/2) * 16 kg/kmol
mass of O = 131.25 kg O 
4 0
3 years ago
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