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DerKrebs [107]
3 years ago
8

What is the Percent yield is 4.65 got copper is produced by 1.87 percent yield is 4.65 got copper is produced when 1.87 grams of

aluminum reacts with excess copper (11) sulfate
Chemistry
1 answer:
marta [7]3 years ago
4 0

Answer:

Percent yield = 69.4%

Explanation:

Given data:

Percent yield  = ?

Actual yield of copper = 4.65 g

Mass of aluminium = 1.87 g

Mass of copper sulfate = excess

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂(SO₄)₃ + 3Cu

Number of moles of Aluminium:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Al with copper.

                 Al           :            Cu

                   2           :              3

                0.07         :              3/2×0.07 =0.105 mol                    

Mass of Copper:(Theoretical yield)

Mass = Number of moles × molar mass

Mass = 0.105 mol × 63.5 g/mol

Mass = 6.7 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 4.65 g/ 6.7 g × 100

Percent yield = 69.4%

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Answer:

a) AgNO3 + KI → AgI + KNO3

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Explanation:

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b) Ba(OH)2 + 2HNO3 → Ba^2+ + 2OH- + 2H+ + 2NO3-

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Answer:

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Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

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Amount of Ag = 5.723 g

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O, \frac{0.10594}{0.02657} \approx 4

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