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2 years ago

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What is your experience about water pollution

1 answer:

vovikov84 [41]2 years ago

7 0

Answer:

water pollution is a process in which water gets polluted due to discharge of city sewage and industrial waste. I was suffering through the water born disease when I drank the contaminated water. The sources of water becomes dirty. It makes environment unbalanced. People suffer from different water born disease when they drink polluted water.

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Where would you have the least weight?

Vikki [24]

In a place with no gravity

Explanation:

Weight is a force exerted by a body in the presence of gravity.

Weight = mass x gravity

Without gravity, there is no force of weight. The more the gravity, the more the weight of a body.

A body will experience weightlessness in a place without no gravity.

Therefore, one will experience the least weight in a place without the pull of gravity.

Learn more:

weight and mass brainly.com/question/5956881

#learnwithBrainly

8 0

3 years ago

2A1 +3CL2, → 2AICI3 what is the reaction

DerKrebs [107]

Answer:

redox reaction

Explanation:

8 0

3 years ago

Read 2 more answers

If an object is moving right at 10 N and a force is applied from the left at 8N, what is the net force on the object?

ryzh [129]

Answer:

If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.

5 0

2 years ago

Whats heptane's formula?

Dovator [93]

Heptane means seven carbon atoms and since the general formula is CnH2n+2, heptane will be C7H16

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3 years ago

Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at

kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

$r = \frac{1 }{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}$

Squaring both sides, we get

$(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}$

Solve for <em>M</em>₂:

$M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}$

$M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}$

$= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}$

7 0

3 years ago