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3 years ago

14

Starting at the age of 40, an average man loses 5%of his hair every year. At what age should an average man expect to have half

his hair left?

1 answer:

ivolga24 [154]3 years ago

6 0

Answer:

50 years old

Step-by-step explanation:

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To determine her power usage, Keri divides up her day into three parts: morning, afternoon, and evening. She then measures he

marusya05 [52]

Answer:

Stratified Sampling

Step-by-step explanation:

Since Keri divides the day into different strata and each unit is selected from each strata randomly. So, it is Stratified Sampling.

Further, In Stratified Sampling population is divided into several groups such that within the group it is homogeneous and between the group it is heterogeneous. And now a selection of each stratum and unit has an equal chance of selection.

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3 years ago

Two pizza delivery drivers compared the mean numbers of deliveries they completed in one day.

myrzilka [38]

Answer:

The mean number of deliveries for driver A is less then the mean for driver B by 3 MADs.

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3 years ago

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Please help asap for a test

son4ous [18]

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3 years ago

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Blow X hold 494 pennies and Bowl Y holds 324 pennie how many pennies should be moved from blow X to bowl Y to make the number of

Tresset [83]

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Step-by-step explanation:

6 0

3 years ago

F(x)=-9x^2-2x and g(x)=3x^2+6x-9, find (f-g)(x) and (f-g)(-4)

Sergio039 [100]

Answer:

$(f-g)(x) = -12x^{2} - 8x + 9$

(f-g)(-4) = -151

Step-by-step explanation:

To find f-g(x) we subtract the common terms. So

$f(x) = -9x^{2} - 2x$

$g(x) = 3x^{2} + 6x - 9$

(f-g)(x)

$(f-g)(x) = f(x) - g(x) = -9x^{2} - 2x - (3x^{2} + 6x - 9) = -9x^{2} - 2x - 3x^{2} - 6x + 9 = (-9 - 3)x^{2} + (-2 - 6)x + 9 = -12x^{2} - 8x + 9$

(f-g)(-4)

$(f-g)(x) = -12x^{2} - 8x + 9$

We replace x by -4

$(f-g)(-4) = -12(-4)^{2} - 8(4) + 9= -151$

(f-g)(-4) = -151

5 0

4 years ago