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VMariaS [17]
3 years ago
5

How many solutions over the complex number system does this polynomial have?

Mathematics
1 answer:
erastova [34]3 years ago
5 0
5 solutions.

The number of complex solutions (roots) of a polynomial function is the degree of the polynomial.
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Robert run the 100 meter dash in 13.5. later he run same distance in 10.3 seconds. how many seconds less did it take him to run
leonid [27]

Answer:

3.2seconds

Step-by-step explanation:

Step one:

Robert run the 100 meter dash in 13.5 seconds

We are told that he later  run same distance in 10.3 seconds

Required.

The time difference in the first dash and the second

Step two:

The first dash took 13.5 seconds

the second took 10.3 seconds

the difference = 13.5-10.3= 3.2seconds

3 0
3 years ago
Gabriella made 36 cookies. She gave away 28 cookies. Use the equation 28 + c = 36 to find c, the number of cookies she kept.
Lera25 [3.4K]

c=8

Hope it helps Hve a nice day

6 0
3 years ago
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If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they
nikklg [1K]

Answer:

9\dfrac{1}{4}

4\dfrac{5}{8}

Step-by-step explanation:

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Again the arbiter has five and three quarters of a cookie i.e. 5\dfrac{3}{4} = \dfrac{23}{4} number of cookies.

Therefore, in total there are (\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4} numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get \dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8} numbers of cookies. (Answer)  

3 0
3 years ago
Charles owes $2,500 on a credit card. The card charges 12% interest compounded continuously. Write a formula that describes how
ella [17]

Answer:

  see below

Step-by-step explanation:

The formula for the amount resulting from P earning interest at rate r continuously compounded is ...

  A = Pe^(rt)

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3 years ago
Math each equation to its graph. Use the drop down menu to describe the equations.
ser-zykov [4K]
1. D linear
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3 years ago
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