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Karolina [17]
3 years ago
14

A woman standing on a hill sees a flagpole that she knows is 65 ft tall. The angle of depression to the bottom of the pole is 14

°, and the angle of elevation to the top of the pole is 18°. Find her distance x from the pole.

Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Answer:

Let the distance between woman and pole be "x".

From diagram,

In ΔOAB,

tan 18 = \frac{Perpendicular}{Base}

tan 18 =  \frac{65 -y}{x}

∴ x =  \frac{65 -y}{tan 18} ................ (1)

In ΔOBC

tan 14 = \frac{Perpendicular}{Base}

tan 14 =  \frac{y}{x}

y = x × tan 14 ..............(2)

equating (2) in (1), we get;

x = \frac{65}{tan 18 + tan 14}

x = \frac{65}{0.574}

∵ tan 18 + tan 14 = 0.574

<em>∴ x = 113.2 ft</em>

<em>i.e. The her distance from the pole is 113.2 ft.</em>

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Given:
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\sf x_1,_2=\cfrac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\times \:1\times \:2}}{2\times \:1}

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\sf x_1,_2\cfrac{-\left(-1\right)\pm \sqrt{-7}}{2\times \:1}

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