Answer:
Look for the y-intercept where the graph crosses the y-axis. Look for the x-intercept where the graph crosses the x-axis. Look for the zeros of the linear function where the y-value is zero.
Step-by-step explanation:
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
do english
Step-by-step explanation:
The answer is 24. To get from one term to the next, you have to find the difference. To get from 52 to 45, you minus 7. It is the same with the other terms. So 31 - 7 = 24
Answer : A
We need to simplify the given expression
Lets factor numerator first
=(2x+1)(x-3)
=(x+5)(x+3)
Now we factor the denominator
=(x+5)(x-4)
=(2x+1)(x-4)
Now we simplify it
Now cancel out same factors. so we left with
Now multiply the factors
