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alexdok [17]
3 years ago
5

A hot air balloon starts with its temperature at 68.7°C and a pressure of 0.987 ATM and volume of 564L at what temperature in de

grees Celsius while its pressure be 0.852 ATM and its volume be 625L
Chemistry
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

54.7°C is the new temperature

Explanation:

We combine the Ideal Gases Law equation to solve this.

P . V = n. R. T

As moles the balloon does not change and R is a constant, we can think this relation between the two situations:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

T° is absolute temperature (T°C + 273)

68.7°C + 273 = 341.7K

(0.987 atm . 564L) / 341.7K = (0.852 atm . 625L) / T₂

1.63 atm.L/K = 532.5 atm.L / T₂

T₂ = 532.5 atm.L / 1.63 K/atm.L → 326.7K

T° in C = T°K - 273 → 326.7K + 273 = 54.7°C

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Perform the following conversions:<br> (a) 68°F (a pleasant spring day) to °C and K.
IgorC [24]

Converting  temperature of 68°F to °C gives 20 °C.

Converting  temperature of 68°F to K gives 293 K.

<h3>What is temperature conversion?</h3>

Temperature conversion is the process of converting  the measurement units of the temperature recorded in a particular unit to another unit.

The various units of Temperature include;

  • degree Celsius
  • degree Fahrenheit
  • degree Kelvin

Temperature is measured with thermometer and it records the hotness or coldness of a body.

<h3>Converting  68°F to °C</h3>

F = 1.8C + 32

(F - 32/1.8) = C

(68 - 32) / 1.8 = C

20 ⁰C = 68 ⁰F

<h3>Converting  20°C to K</h3>

0 °C  = 273 K

20 °C  = 273 + 20 = 293 K

Learn more about temperature conversion here: brainly.com/question/23419049

#SPJ1

3 0
2 years ago
What happens to the sugars that are made during photosynthesis?
KiRa [710]
The sugars (c6h12o6) or the glucose that is made during photosynthesis is turned into glucose cellulose or starch that the plant can use for energy and food for the plant. Hope this helps.
8 0
4 years ago
Cobalt-63 has a half-life of 5.3 years. If a pellet that has been in storage for 15.9 years contains 40.0g of Cobalt-63, how muc
Cerrena [4.2K]

Answer:

320 g  

Step-by-step explanation:

The half-life of Co-63 (5.3 yr) is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:  

  No. of               Fraction         Mass

half-lives   t/yr   Remaining   Remaining/g

      0        0              1

      1         5.3           ½

     2        10.6           ¼

     3        15.9           ⅛                 40.0

     4        21.2           ¹/₁₆

We see that 40.0 g remain after three half-lives.

This is one-eighth of the original mass.

The mass of the original sample was 8 × 40 g = 320 g

5 0
3 years ago
What is the minimum pressure in kPa that must be applied at 25 °C to obtain pure water by reverse osmosis from water that is 0.1
Yuri [45]

Answer:

The minimum pressure should be 901.79 kPa

Explanation:

<u>Step 1: </u>Data given

Temperature = 25°C

Molarity of sodium chloride = 0.163 M

Molarity of magnesium sulfate = 0.019 M

<u>Step 2:</u> Calculate osmotic pressure

The formula for the osmotic pressure =

Π=MRT.

⇒ with M = the total molarity of all of the particles in the solution.

 ⇒ R = gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 25 °C = 298 K

NaCl→ Na+ + Cl-

MgSO4 → Mg^2+ + SO4^2-

M = 2(0.163) + 2(0.019 M)

M = 0.364 M

Π = (0.364 M)(0.08206 atm-L/mol-K)(25 + 273 K)

Π = 8.90 atm

(8.90 atm)(101.325 kPa/atm) = 901.79 kPa

The minimum pressure should be 901.79 kPa

6 0
4 years ago
Suppose there are two known compounds containing the generic elements X and Y. You have a 1.00-g sample of each compound. One sa
Lapatulllka [165]

I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y, for the following reason: 

If you look at the combining masses of X and Y in each of the two compounds, 

The first compound contains 0.25g of X combined with 0.75g of Y 
so the ratio (by mass) of X to Y = 1 : 3 

The second compound contains 0.33 g of X combined with 0.67 g of Y 
so the ratio (by mass) of X to Y = 1 : 2 

Now, you suppose to prepare each of these two compounds, starting with the same fixed mass of element Y ( I will choose 12g of Y for an easy calculation!) 

The first compound will then contain 4g of X and 12g of Y 
The second compound will then contain 6g of X and 12g of Y 

<span>The ratio which combined the masses of X and the fixed mass (12g) of Y
= 4 : 6 
<span>or 2 : 3 </span>

So, the ratio of MOLES of X which combined with the fixed amount of Y in the two compounds is also = 2 : 3 </span>

The two compounds given with the plausible formula must therefore contain the same ratio.

8 0
3 years ago
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