1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexdok [17]
3 years ago
5

A hot air balloon starts with its temperature at 68.7°C and a pressure of 0.987 ATM and volume of 564L at what temperature in de

grees Celsius while its pressure be 0.852 ATM and its volume be 625L
Chemistry
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

54.7°C is the new temperature

Explanation:

We combine the Ideal Gases Law equation to solve this.

P . V = n. R. T

As moles the balloon does not change and R is a constant, we can think this relation between the two situations:

P₁ . V₁ / T₁ = P₂ . V₂ / T₂

T° is absolute temperature (T°C + 273)

68.7°C + 273 = 341.7K

(0.987 atm . 564L) / 341.7K = (0.852 atm . 625L) / T₂

1.63 atm.L/K = 532.5 atm.L / T₂

T₂ = 532.5 atm.L / 1.63 K/atm.L → 326.7K

T° in C = T°K - 273 → 326.7K + 273 = 54.7°C

You might be interested in
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
3 years ago
Cosity a letter to our mother
kotykmax [81]

An answer befitting your question…

Hi mom, I’m having troubles with my teachers. They are cruel to me and I cannot concentrate. I think if we changed schools it would be much better. Thank you mom.
6 0
3 years ago
Water is unique because the density of it's solid is less than the density of it's liquid. Describe how life would be different
Andreas93 [3]

Ice caps would float therefore providing insulation for aquatic life and ensuring they do not freeze due to the cool temperature.

6 0
3 years ago
Which intermolecular force would affect melting point the most?
Anastaziya [24]

Answer:

Hydrogen bonding

Explanation:

3 0
2 years ago
How many atoms are in 3 C2H6
mart [117]
Very good question, I can easily answer that for you if it has 3 moles of ethane contains 6 mole of carbon atoms. so that means 3 moles of ethane contains 18 mole of hydrogen atoms.

Have a blessed day and God bless.
8 0
3 years ago
Read 2 more answers
Other questions:
  • HELP PLS<br> kakwkwkwkkwkwkw
    9·1 answer
  • When light bends as it passes from one transparent object to another, the light is
    8·2 answers
  • Someone please help!! i don’t know how to do this
    13·1 answer
  • A bond in which an electron pair is unequally shared by two atoms is:__________
    15·1 answer
  • Which of the following solutions will have the highest concentration of chloride ions?
    12·1 answer
  • Consider the reaction:
    14·1 answer
  • Put atom in order from most to lest​
    10·1 answer
  • Describe how to use a transfer pipet to deliver 10.00 mL of liquid by placing the steps in the correct order.
    13·1 answer
  • Which one of the give elements the least reactive?
    13·2 answers
  • Calculate the molality of a 5.51 M ethanol (C2H5OH) solution whose density is 0.9349 g/mL
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!